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Tresset [83]
3 years ago
8

Consider two flat plate airfoils as lumped "lifting elements" in a tandem arrangement, where the second airfoil is located at so

me distance downstream from the first airfoil. The chords and attack angles of both airfoils are the same. Find the circulations of these airfoils in terms of the free-stream velocity U , attack angle  , chord c , and the distance between the airfoils’ leading edges d . Which airfoil generates higher lift force and why? Discuss the effect of the distance between the airfoils on their aerodynamic interaction.

Engineering
1 answer:
timurjin [86]3 years ago
7 0

Answer:

Explanation:

Attached is the solution

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What is the perimeter of 14-7 and 3-4
Goshia [24]

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If you mean two sides are 7 and two sides are 14 then you'd have 42

and for the second you'd have 14

Explanation:

7 + 7 = 14, 14 + 14 = 28, 14 + 28 = 42

3 + 3 = 6, 4 + 4 = 8, 8 + 6 = 14

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answer c

Explanation:

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The Lamborghini SCV12 has 830 horse power.
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A 132mm diameter solid circular section​
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5 0
3 years ago
A cylindrical brass rod has a length of 5.00cm extending from a holder and a diameter of 4.50mm. Its Young's modulus is 98.0GPa.
Galina-37 [17]

Answer:

elongation of the brass rod is 0.01956 mm

Explanation:

given data

length = 5 cm = 50 mm

diameter = 4.50 mm

Young's modulus = 98.0 GPa

load = 610 N

to find out

what will be the elongation of the brass rod in mm

solution

we know here change in length formula that is express as

δ = \frac{PL}{AE}    ................1

here δ is change in length and P is applied load  and A id cross section area and E is Young's modulus and L is length

so all value in equation 1

δ = \frac{PL}{AE}  

δ = \frac{610*50}{\frac{\pi}{4} * 4.50^2 * 98*10^3}  

δ = 0.01956 mm

so elongation of the brass rod is 0.01956 mm

7 0
3 years ago
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