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2 answers:
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Answer:
7.7 kN
Explanation:
The capacity of a material having a crack to withstand fracture is referred to as fracture toughness.
It can be expressed by using the formula:
where;
fracture toughness K = 137 MPa
geometry factor Y = 1
applied stress = ???
crack length a = 2mm = 0.002
∴
Now, the tensile impact obtained is:
P = A × σ
P = 1728.289 × 4.5
P = 7777.30 N
P = 7.7 kN
Answer:
1.44 mm
Explanation:
Compute the maximum allowable surface crack length using
where E is the modulus of elasticity,
is surface energy and
is tensile stress
Substituting the given values
The maximum allowable surface crack is 1.44 mm