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ICE Princess25 [194]
3 years ago
9

Rubber bushings are used on suspensions to

Engineering
1 answer:
Harlamova29_29 [7]3 years ago
4 0
D. All of the above
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Chemical compounds that are created by a string or smaller repeating units are
yKpoI14uk [10]

Answer:

The correct approach will be "Polymer".

Explanation:

  • A polymer, because it has a very broad molecular structure, seems to be a class or kind of organic solid. It is indeed a material consisting of long sequences, or monomers, of simplified components.
  • The existence of a large number of monomers which have been mentioned several times seems to be the principal design characteristic of polymeric materials.
6 0
3 years ago
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2. A hammer drill has an adjustable ring that can<br> be turned to adjust the<br> ___.
SOVA2 [1]
Number of drill blows per minute. hope this helps !!
4 0
3 years ago
Determine the initial void ratio, the relative density and the unit weight (in pounds per cubic foot) of the specimens for each
Elina [12.6K]

The initial void ratio is the <em>parameter </em>which is used to show the structural foundations for each <em>specimen of sand </em>so that the method and speed of compression would be <em>measured</em>.

Relative density is the mass per unit volume of each specimen of sand which is <em>measured </em>and it has to do with the<em> relative ratio</em> of the density of the sand.

Unit weight is the the exact weight per cubic foot of the sand which is measured.

Please note that your question is incomplete so I gave you a general overview to help you better understand the concept

Read more here:

brainly.com/question/15220801

5 0
3 years ago
. A Carnot heat pump is to be used to heat a house and maintain it at 22 °C in winter. When the outdoor temperature remains at 3
max2010maxim [7]

Answer:

The Carnot heat pump must work 3.624 hours per day to keep the temperature constant inside the house.

Explanation:

The net heat daily loss of the house is:

Q_{losses} = \left(76000\,\frac{kJ}{h}\right)\cdot (24\,h)

Q_{losses} = 1.824\times 10^{6}\,kJ

In order to keep the house warm, given heat must be equal to heat losses:

Q_{H} = Q_{losses}

Besides, the Coefficient of Performance for a Carnot heat pump is:

COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}

Where,

T_{L} - Temperature of the cold reservoir (Outdoors), measured in Kelvin.

T_{H} - Temperature of the hot reservoir (House), measured in Kelvin.

Given that T_{L} = 276.15\,K and T_{H} = 295.15\,K, the Coefficient of Performance is:

COP_{HP} = \frac{295.15\,K}{295.15\,K-276.15\,K}

COP_{HP} = 15.534

For a real heat machine, the Coefficient of Performance is determined by the following expression:

COP_{HP} = \frac{Q_{H}}{W}

Where:

Q_{H} - Heat received by the house, measured in kilojoules.

W - Work consumed by the Carnot heat pump, measured in kilojoules.

The daily work consumed is now cleared in the previous expression:

W = \frac{Q_{H}}{COP_{HP}}

W = \frac{1.824\times 10^{6}\,kJ}{15.534}

W = 117419.853\,kJ

The working time is calculated by dividing this result by input power. That is:

\Delta t = \frac{W}{\dot W}

\Delta t = \left(\frac{117419.853\,kJ}{9\,kW} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}\right)

\Delta t = 3.624\,h

The Carnot heat pump must work 3.624 hours per day to keep the temperature constant inside the house.

8 0
3 years ago
Limited time only for christmas give yourself free 100 points YES YES muhahahahhaha
Setler79 [48]
Answer:

Thank you so much and may god bless you.
6 0
2 years ago
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