Rubber bushings are used on suspensions to

Kieran and Kurt spend most of their day performing physical labor, aligning materials, and inspecting projects for quality and s

xxMikexx [17]

Answer:

Kieran is a Carpenter, and Kurt is a Drafter

Explanation:

Among all the professions listed, Kurt can only possibly be a Drafter. A Drafter is an engineering technician who makes detailed technical drawings or plans for machinery, buildings, electronics, infrastructure, sections, etc. Drafters make use of computer software and manual sketches to convert the designs, plans, and layouts of engineers and architects into a set of technical drawings. All the other professions will at some point need for the professional to stand and work at an height above the ground except for a drafter, whose feet will remain on the ground at almost all times.

5 0

3 years ago

Read 2 more answers

A metal having a cubic structure has a density of , an atomic weight of , and a lattice parameter of Å One atom is associated wi

Veronika [31]

Answer:

Explanation:

Answer: The crystal structure of the metal is BCC

Explanation:

we first calculate the volume of the unit cell.

Volume of unit cell= (a°)^3.

The lattice parameter here is a°.

Substitute (6.13 * 10^-8)cm for a°.

Volume of unit cell = (6.13 * 10^-8)^3 = 2.3034 * 10^-22 cm^3/cell.

To determine the crystal structure we use

Density (p) = {(Number of atoms per cell) (Atomic mass)} / {(volume of unit cell)(Avogrado constant)}.

Substitute 1.892g/cm^3 for p (6.02*10^23) atoms/mol for Avogrado constant 1.3921g/mol.

For atomic mass and (2.3034 * 10^-22) cm^3/cell for unit cell.

1.892g/cm^3 = {(Number of atoms per cell) (1.3291g/mol)} / {(2.3034 * 10^-22) (6.02 * 10^23 atoms/mol)}.

Changing the subject of formula we have :

Number of atoms per cell = {(2.3034 * 10^-22) * (6.02 * 10^23) * 1.892} / 132.91

Number of atoms per cell = 2.

Since the number of atoms per cell is 2, :. the crystal structure of metal is BCC.

Note: p = density

a° = a subscript o

4 0

3 years ago

2. Given that a quality-control inspection can ensure that a structural ceramic part will have no flaws greater than 100 µm (100

MA_775_DIABLO [31]

Answer:

SiC=169.26 Mpa

Partially stabilized zirconia=507.77 Mpa

Explanation:

Stress intensity, K is given by

$K=\sigma Y\sqrt{\pi a}$ hence making $\sigma$ the subject where $\sigma$ is applied stress, Y is shape factor, a is crack length

$\sigma=\frac {K}{Y\sqrt{\pi a}}$ substituting the given figures and assuming shape factor, Y of 1

$\sigma=\frac {3}{1\sqrt{\pi 100*10^{-6}}}= 169.2569\approx 169.26 Mpa$

<u>Stabilized zirconia </u>

Stress intensity, K is given by

$K=\sigma Y\sqrt{\pi a}$ hence making $\sigma$ the subject where $\sigma$ is applied stress, Y is shape factor, a is crack length

$\sigma=\frac {K}{Y\sqrt{\pi a}}$ substituting the given figures and assuming shape factor, Y of 1

$\sigma=\frac {9}{1\sqrt{\pi 100*10^{-6}}}= 507.7706\approx 507.77 Mpa$

7 0

3 years ago

대한민국의 주권은 국민에게 있고. 예비비의 지출은 차기국회의 승인을 얻어야 한다, 대통령은 국가의 안위에 관계되는 중대한 교전상태에 있어서 국가를 보위하기 위하여 긴급한 조치가 필요하고 국회의 집회가 불가능한 때에 한하여 법률의

mote1985 [20]

qué qué qué qué qué qué qué

8 0

3 years ago

. A two-dimensional fluid motion is represented by a point vortex of strength Γ set at distance c from an infinite straight soli

Lostsunrise [7]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

8 0

3 years ago