Rubber bushings are used on suspensions to

Help me Pls

cupoosta [38]

Answer:

you got this

Explanation:

try this relax your brain

6 0

3 years ago

Give a big-Oh characterization, in terms of n, of the running time of the Ex1-EX5 functions as shown in following Code Fragment

mash [69]

Answer:

Hello there, Please follow the step by step explanations for answer.

Explanation:

Hello there, Please follow the step by step explanations for answer.

Ex1 ( A):

it depends on n

=> O(n)

2.)

O(n/2) which is equal to O(n)

3.)O(n^2)

4.)O(2n) ==> O(n)

5.)O(n^3)

Also, see file attachment on this question for more clarity. Thanks and all the best.

8 0

3 years ago

If a ball is dropped from a height its velocity will increase until it hits the ground, assuming that aerodynamic drag due to th

worty [1.4K]

Answer:

g = 9.69 m/s²

Explanation:

given,

height from where ball is dropped = 800 cm = 8 m

impact velocity = 41 ft/s = 41 × 0.3048 = 12.45 m/s

acceleration due to gravity = ?

initial potential energy is given by

PE = m g h

= m g × 8

= 8 mg..............(1)

now final kinetic energy

$KE= \dfrac{1}{2}m(v)^2$

$KE= \dfrac{1}{2}m(12.45)^2$

=77.50 m.....................(2)

comparing equation (1) to (2)

8 mg = 77.50 m

g = 77.5/8

g = 9.69 m/s²

6 0

3 years ago

5 Systems Modeling

Nesterboy [21]

Answer: None of the above

Explanation:

Business process modeling refers to the graphical representation of the business processes of a company, which is vital in the identification of potential improvements.

Business pticess modelling can be done through graphing methods, like data-flow diagram, flowchart etc. It is vital as business managers can effectively and quickly communicate their ideas.

It also enhances the customization of business processes, enhances the competitive advantage and enhances the process communication as well.

Therefore, the answer to the question will be "None of the above".

5 0

3 years ago

7 A very large thin plate is centered in a gap of width 0.06 m with different oils of unknown viscosities above and below; one v

sineoko [7]

Answer:

$\mu_1\approx 0.967$

$\mu_2\approx 1.933$

Explanation:

The viscosities above and below the plate are given by

$\mu_2=2\mu_1$ where $\mu_1$ and $\mu_2$ are viscosities of fluid below and above plate respectively

Force on plate due to top layer of the fluid

$\tau_1=\mu_1\frac {\triangle u}{\triangle y}$ where $\triangle u$ and $\triangle y$ are the velocity of plate and gap between the plate and upper surface respectively.

$\tau_1=\mu_1\times \frac {0.3}{0.03}=10\mu_1$

Force on plate due to bottom layer of the fluid is given by

$\tau_2=\mu_2\frac {\triangle u}{\triangle y}$ where $\triangle u$ and $\triangle y$ are the velocity of plate and gap between the plate and upper surface respectively