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2 years ago

Suppose a mouse is placed in the maze at the right. If each direction

Mathematics

1 answer:

irakobra [83]2 years ago

8 0

You have to give us a picture or somthing elaborate please

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I’m confused on this one

erastovalidia [21]

In the chart of the triangle it shows that the variable b is the base. It also give us the equation for area 1/2bh (half of base * height)

Now we just plug in the values we are given

1/2bh

1/2(10*13)

1/2(130)

The area of the triangle is 65 ft

4 0

2 years ago

Read 2 more answers

1.07, 1.7 and 1.007 in order from<br><br>greatest to least

Vladimir [108]

1.7 , 1.07 , 1.007 greatest to least

4 0

2 years ago

Hat is the solution to the system of equations?

Dima020 [189]

Answer:

(–19, 55)

Step-by-step explanation:

y = –3x – 2 equation 1

5x + 2y = 15 equation 2

using equation 1 in equation 2 we have:

5x + 2(–3x – 2) = 15

5x –6x – 4 = 15

-x = 15+4

x=-19

using equation 1:

y = -3(-19)- 2

y= 57-2

y= 55

5 0

3 years ago

A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$

Similarly, but exchanging the role of x and y, we compute the length of BC:

$\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5$

So, the area of the rectangle is $\overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50$

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

$\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3$

$\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4$

So, the area of the portion located in the third quadrant is $\overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12$

This means that the ratio between the two area is

$\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}$

If we want this ratio to be a percentage, just make sure that the denominator is 100:

$\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%$

3 0

2 years ago

Find the area of the shape shown below

Sonja [21]

Answer:

Step-by-step explanation:

take the triangle away from the square you will get 9 for the square 3x3 you get the 3 from 7 because 7-3=4 the 4 if for the triangle 4x3=12 divided by 2 bc its a triangle u get 6 6+9=15

3 0

2 years ago