Answer:
Real images are formed where rays of light actually converge, whereas virtual images occur with they are perceived to converge. Real images can be produced by passing light through converging lenses or with a concave mirror of some sort.
Explanation:
hope that helped a little :)
Answer:
The ratio is 1:1
Explanation:
Firstly we are told the in (a) we have a force which A given to be: FA
We are then told the are two other forces which a B and C which are equal.
These forces are given to be F and 19.5° away from A.
We are then told that the force on the elephant is now three times, of what it was when we only had force A.
Since we are told that B and C are eqaula.
If we say FA = 2N
Then in order for it to be three times, we would have to add 4N since it was the only force present at the time.
If we add two equal forces, then we can devide that 4 by 2.
We then find out that F =2N
and thus equal to FA.
Therefore the ratio of F/FA is
!:1
To solve this problem it is necessary to apply the concepts related to diffraction through a circular opening.
By definition the angular resolution is given by
![\theta = 1.22\frac{\lambda}{D}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.22%5Cfrac%7B%5Clambda%7D%7BD%7D)
Where,
![\lambda = Wavelenght](https://tex.z-dn.net/?f=%5Clambda%20%3D%20Wavelenght)
D = Diameter of the lens aperture.
Our values are given as,
![\lambda = 600*10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20600%2A10%5E%7B-9%7Dm)
![d = 1.5*10^{-2}m](https://tex.z-dn.net/?f=d%20%3D%201.5%2A10%5E%7B-2%7Dm)
Therefore replacing,
![\theta = 1.22\frac{600*10^{-9}}{1.5*10^{-2}}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.22%5Cfrac%7B600%2A10%5E%7B-9%7D%7D%7B1.5%2A10%5E%7B-2%7D%7D)
![\theta = 4.88*10^{-5} rad](https://tex.z-dn.net/?f=%5Ctheta%20%3D%204.88%2A10%5E%7B-5%7D%20rad)
Therefore the angular separation is ![4.88*10^{-5} rad](https://tex.z-dn.net/?f=4.88%2A10%5E%7B-5%7D%20rad)
A. Upwelling is the rising of cold water from deep layers to replace warm surface water.
Answer:
15km/hr
Explanation:
The average speed for the entire trip is the sum of the total distance traveled divided by the total time of the trip.
Total time = 4hr
distance for the first 3hrs = 50km
distance for the last 1hr = 10km
Total distance = 50km + 10km = 60km
Now;
Average speed =
Insert the parameters and solve;
Average speed =
= 15km/hr