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enyata [817]
3 years ago
8

Help me it just one question I need pls

Physics
1 answer:
Mkey [24]3 years ago
4 0

Answer:

yes its true

Explanation:

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Rosalind is an impulsive child who seldom waits for her turn when playing with other children. Rosalind's father is also an impu
wariber [46]

Answer:

Alburt Bandura

Explanation:

Rosalind has learned to be impulsive and seldom waits for her turn when playing with other children, this trait she has learned  from her father, who is also an impulsive man.

The theorist who would most likely suggest that Rosalind has learned to be impulsive from watching her father is Alburt Bandura. Alburt in his famous Bebo Doll experiment confirmed that children learn from the adults behavior in their life.

3 0
3 years ago
A jogger runs 224 meters eastward, then 156 meters
yawa3891 [41]

Explanation:

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

Distance = 224 m + 156 m + 84 m + 248 m = 712 m

Displacement = 224 m − 156 m + 84 m − 248 m = -96 m

Displacement = 96 m westward

6 0
3 years ago
Jeremy is walking through the woods, marking diseased trees for removal. He walks for 2.44 km, at a heading of 13.9° west of nor
Ludmilka [50]

We conclude that Jeremy walked 2.37km North and 0.59 km West.

<h3>How to get the North and West components?</h3>

We can assume that the distance that he walked is the hypotenuse of a right triangle, like the one you can see in the image below.

There, you can see that the adjacent cathetus would be the displacement in the North direction, while the opposite cathetus would be the displacement in the West direction.

Then we can use the relations.

  • Sin(θ) = (opposite cathetus)/(hypotenuse)
  • Cos(θ)  = (adacent cathetus)/(hypotenuse).

With θ = 13.9° and hypotenuse = 2.44km

Solving these two we will get:

sin(13.9°) = Y/2.44km

sin(13.9°)*2.44km = Y = 0.59 km

cos(13.9°) = X/2.44km

cos(13.9°)*2.44km = X = 2.37km

So we can conclude that he walked 2.37km North and 0.59 km West.

If you want to learn more about right triangles, you can read:

brainly.com/question/2217700

7 0
3 years ago
The moon has a mass of 1×10^22 kg, and the gravitational field strength at a distance r from the planet is 0.001 n/kg. what is t
CaHeK987 [17]

When I divided by 6, I got W(moon) = mg(moon) = 10 x 10/6 = 16.7N (the moon's gravity is only 1/6 that of Earth in this case). 100N is equal to W(Earth) = mg(Earth) = 10 x 10. On the moon and the Earth, m = 10 kg.

How can you determine the strength of Earth's gravitational field at the moon?

M = 6 10 24 K g is the mass of the earth, and g = - G M R 2 is the gravitational field of the earth at the point of the moon. The distance between the earth and moon is 84 10 8 meters. field of gravitation.

How do you determine the distance between Earth and the moon where the gravitational field is at its weakest?

You only discover points where the forces from all of the different local bodies are in balance, or equal to each other, because there is no place in the universe where the gravitational field intensity is zero. All bodies, not just the Earth and Moon, must be taken into account in the computation to arrive at these positions.

To know more about gravitational field strength at moon visit;

brainly.com/question/20909424

#SPJ4

4 0
2 years ago
What happens to the piece of steel?
anyanavicka [17]
The answer should be c....
6 0
4 years ago
Read 2 more answers
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