Answer: Pressure increases as the depth increases.
Acceptame para ser amigos y luego te ayudo
( 8.10) x 10^4 J = ½(1010kg)V²
<span>......................= 505V² </span>
<span>( 8.10) x 10^4 J =[(.0505) x 10^4] V² ........<==10^4 cancels </span>
<span>8.10 = .0505 V² </span>
<span>.........______ </span>
<span>V = ²√ 160.4 </span>
<span>V= 12.6 m/s </span>
<span>(that's 12.6m/sec(1km/1000m)(3600secs/1hr) = 45.36kph) </span>
<span> my diagram is wrong, it is just an ordinary car, </span>
Answer:
Er = 108 [J]
Explanation:
To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.
200 - 44 - 48 = Er
Where:
Er = remaining energy [J]
Er = 108 [J]