The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.
The reaction is:
2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)
The enthalpy of reaction (1) is given by:
(2)
Where:
r: is for reactants
p: is for products
The bonds of the compounds of reaction (1) are:
- 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
- 7O₂: 7 moles of 1 O=O bond
- 4CO₂: 4 moles of 2 C=O bonds
- 6H₂O: 6 moles of 2 H-O bonds
Hence, the enthalpy of reaction (1) is (eq 2):

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.
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Is a solid because liquids are not is not that close and gas is very far apart.
Answer : Density of any particular matter remains the same at any concentration at any weight.
Density does not varies with the concentration. The formula for density is mass / volume.
So if the mass changes the density will change accordingly, also if the volume changes the density will get changed.
because, of the above reasons density is referred as a characteristic property of matter.
Answer:
The Gwichʼin or Kutchin are an Athabaskan-speaking First Nations people of Canada and an Alaska Native people. They live in the northwestern part of North
Explanation: