Molas mass C6H12O6 = 180.15 g/mol
1 mole C6H12O6 -------------- 180.15 g
?? molesC6H12O6 ------------ 3.10x10⁻³ g
3.10x10⁻³ x 1 / 180.15 => 0.00001720 moles
1 mole ------------------------- 6.02x10²³ molecules
0.00001720 moles ---------- ??
0.00001720 x (6.02x10²³) / 1 => 1.035x10¹⁹ molecules
Answer:
The limiting reactant is B.
Explanation:
The equation for the reaction is given below:
2A + 3B —> C + D
The limiting reactant can be obtained as follow:
From the equation above,
2 units of A reacted with 3 units of B.
Therefore, 5 units of A will react with = (5 x 3) /2 = 7.5 units of B.
From the calculation made above, we can see that it will take a higher unit of B i.e 7.5 units than what was given i.e 6 units to react completely with 5 units of A.
Therefore, B is the limiting reactant and A is the excess reactant.
Answer:
[OH⁻] = 1.77 × 10⁻¹¹ M
Solution:
In order to calculate concentration of hydroxide ion i.e. [OH⁻] first we will find the pOH by using following relation,
pH + pOH = 14
Putting value of pH given and solving for pOH,
3.25 + pOH = 14
pOH = 14 - 3.25
pOH = 10.75
As ,
pOH = -log [OH⁻]
So,
[OH⁻] = 10^-pOH
Putting value of pOH,
[OH⁻] = 10⁻¹⁰·⁷⁵
[OH⁻] = 1.77 × 10⁻¹¹ M
