Answer:
6
Step-by-step explanation:
2 + (1/10)(1/5)(1/10)2000 = 2 + (1/500)(2000) = 2 + 4 = 6
This is a system of linear equations. First, you can add the two equations together to eliminate the y so that you can solve for x:
-5x + -7x = 0 + -96
-12x = -96
x = 8
Use x to solve for y:
-5 * 8 + 8y = 0
Add 40 to both sides and divide by 8:
y = 5
So, x = 8 and y = 5.
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A 
Answer:
One ticket equals $169
Step-by-step explanation:
The family buys 4 airline tickets online.
The travel insurance costs $19 per ticket.
The total cost is $752.
A.
An equation that models this problem could be
Basically, we know that the insurance costs $19 which represents an additional costs after the price per ticket, that's why we need to add them. Then, we know that the familiy bought 4 tickes, that's why we multiply by 4, and finally, the total cost must be equal to 752, according to the problem.
B.
To find the price of one ticket, we just need to solve the equation for
Therefore, one ticket costs $169.
