Answer:
m = E × Q
And Q = I × t
m = E × I × t
Where m = mass in grams
Q = quantity of electricity in coulomb
I = current in ampere
t = time in seconds
E = electrochemical equivalent of the substance
Explanation:
A. a mutual attraction between the nuclei and electrons in two different atoms.
A single sodium ion will combine due to its charge on it
Na^+
The single sodium ion has total one positive charge on it. so it requires only one electron or can bond to one negative charge
in the given polyatomic anions
a) CO3^-2 : it has two negative charge. So it will react with two sodium ions
it will forms Na2CO3
b) PO4^-3 :it has three negative charge. So it will react with three sodium ions
it will forms Na3PO4
c) SO4^-2 : it has two negative charge. So it will react with two sodium ions
it will forms Na2SO4
d) NO3^-1: it has one negative charge. So it will react with one sodium ion
it will forms NaNO3
Hence the correct answer is
Nitrate ion will react with single sodium ion as
Na+ + NO3- ---> NaNO3
Answer:
30 μmol/L
Explanation:
<em>A chemist prepares a solution of barium chloride by measuring out 8.9 μmol of barium chloride into a 300mL volumetric flask and filling the flask to the mark with water.
</em>
<em>
Calculate the concentration in μmol L of the chemist's barium chloride solution. Round your answer to 2 significant digits.</em>
<em />
The chemist has 8.9 μmol of solute (barium chloride) and he adds water until the mark of 300 mL in the container, which is the volume of the solution. We will need the conversion factor 1 L = 1000 mL. The concentration of barium chloride in μmol/L is:
Answer:
The correct option is: B. 33%
Explanation:
Orbital hybridisation refers to the mixing of atomic orbitals of the atoms in order to form new hybrid orbitals. The concept of orbital hybridization is used to explain the structure of a molecule.
The sp² hybrid orbitals are formed by the hybridization of one 2s orbital and two 2p orbitals. <u>The three sp² hybrid orbitals formed have 33% s character and 67% p character.</u>
