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seraphim [82]
3 years ago
10

If a quadrilateral does not have two pairs of opposite sides that are parallel, then it may be a _____.

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0
C. Trapezoid

A trapezoid is the only option of the 5 that is not composed of two sets of parallel lines
N76 [4]3 years ago
4 0
A trapezoid is the answer i believe
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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
Plz help sovle these one-step equations
USPshnik [31]
The answer to the question

7 0
3 years ago
Can someone please help me real quick?​
Ivahew [28]

Answer:

Big square - unshaded = shaded

((8+4)X(10+5))-(10X8)=100

Answer: 100

Step-by-step explanation:

8 0
2 years ago
If 3f(x) - f(1/x) = x^2 , what is the value of f(1/2)?<br>and it's from R-{0} to R obviously.
GarryVolchara [31]

Answer:

0.59375‬

Step-by-step explanation:

3f(x) - f(1/x) = x^2

x = 2:   3f(2) - f(1/2) = 2^2

x = 1/2: 3f(1/2) - f(2) = (1/2)^2

Let a = f(1/2) and b = f(2):

3b - a = 4; 3a - b = 1/4

3b - 4 = a

3(3b-4) - b = 1/4

8b = 12 + 1/4

b = 1.53125‬

3 * 1.53125‬ - 4 = a

a = 0.59375‬

8 0
3 years ago
The radius of a circle is 8 inches. What is the circle's area?
sveta [45]

Answer:

200.96

Step-by-step explanation:

3.14 x (8x8) = 200.96

8 0
3 years ago
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