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Talja [164]
3 years ago
13

Help i need to pass this class

Chemistry
1 answer:
navik [9.2K]3 years ago
4 0

Answer: It would be B

Explanation: a magnet moves from north to south

due to pole attraction is more in the north region

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Structural formula and type of reaction for each
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D. propane and hydrogen gass
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In the vertical columns of the periodic table, as the atomic numbers increase:
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A.) The number of electron shells increases.
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How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0
4 years ago
Consider the reaction of ethyl acetate with sodium hydroxide: CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq)+C2H5OH(aq) The reaction is fi
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Answer: The rate law is rate=k[CH_3COOC_2H_5]^1[NaOH]^1

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For the given reaction:

CH_3COOC_2H_5(aq)+NaOH(aq)\rightleftharpoons CH_3COONa(aq)+C_2H_5OH(aq)

k= rate constant

Rate law: rate=k[CH_3COOC_2H_5]^x[NaOH]^y

For the given rate law:

y =1 =  order with respect to NaOH

n = total order = 2

2= (x+y)

2= (x+1)

x= 1

Thus order with respect to CH_3COOC_2H_5 is 1 and rate law is : rate=k[CH_3COOC_2H_5]^1[NaOH]^1

6 0
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If a patient\'s blood pressure is 145 over 85 mmHg, what is it in atmospheres (atm)?
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In 1(atm) the patients blood is 760 mmHg
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