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Rainbow [258]
3 years ago
13

How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions

Chemistry
1 answer:
omeli [17]3 years ago
5 0

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

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using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (c6h6).
aliya0001 [1]

the amount of heat produced from the combustion of 24.3 g benzene (c6h6) is ΔH = -976.5 kJ

There are two moles of benzene involved in the process (C6H6). Since the heat of this reaction is -6278 kJ, the burning of 2 moles of benzene will result in a heat loss of 6278 kJ. This reaction is exothermic.

Enthalpy, or the value of H, is a unit of measurement for heat that relies on the amount of matter present (number of moles).

Thus, 24.3 g of benzene contains:

n = mass/molar mass, where n = 24.3/78.11, and n = 0.311 moles.

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0.311 moles =x

By the straightforward direct three rule:

2x = -1953.08 x = -976.5 kJ

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4 0
1 year ago
NEED HELP with 7. 8. 9. 10. 11. 12. And 14 !!
aleksley [76]

Answer:

1.      0.00040 calories

2.   8.57 calories

3.   0.196 calories

4.  68 calories

5. 243 calories

6.  83680 joules

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9. 556 (it says calories to calories so it wouldn't change)

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Explanation:

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3 years ago
How many molecules are contained in 103.4g of sulfuric acid?
Ierofanga [76]
<h3>Answer:</h3>

1.827 × 10²⁴ molecules H₂S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Compounds</u>

  • Writing Compounds
  • Acids/Bases

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

103.4 g H₂S (Sulfuric Acid)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 103.4 \ g \ H_2S(\frac{1 \ mol \ H_2S}{34.09 \ g \ H_2S})(\frac{6.022 \cdot 10^{23} \ molecules \ H_2S}{1 \ mol \ H_2S})
  2. Multiply:                                                                                                            \displaystyle 1.82656 \cdot 10^{24} \ molecules \ H_2S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 4 sig figs.</em>

1.82656 × 10²⁴ molecules H₂S ≈ 1.827 × 10²⁴ molecules H₂S

4 0
3 years ago
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