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torisob [31]
3 years ago
12

a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done? a person expended 500 newtons to move

a full wheelbarrow 30 meters how much work was done?
Physics
1 answer:
stiv31 [10]3 years ago
6 0
<span>A person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?

</span>In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. The work done would be calculated as follows:
</span>
W = F x d = 500 N (30 m) = 15000 J or 15 kJ
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3 years ago
A rope pulls a 20 kg box up. If the tension in the rope is 275 N, what is the acceleration of the box?
Nana76 [90]

Answer:

<h3>The answer is 13.75 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

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a =  \frac{275}{20}  =  \frac{55}{4}  \\

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<h3>13.75 m/s²</h3>

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4 0
3 years ago
An object starts from rest at the origin (x0 = 0) and travels in a straight line with a constant acceleration (a = constant). Su
agasfer [191]

Answer:

a=(6.8)\ m/s^2

Explanation:

Given that,

An object starts from rest at the origin (x₀ = 0) and travels in a straight line with a constant acceleration (a = constant).

The relation between the position (x) and time (t) is given by :

x=(3.4t^2)\ m/s^2

Let v is the velocity of the object.

v=\dfrac{dx}{dt}

v=\dfrac{d(3.4t^2)}{dt}

v=(6.8t)\ m/s

Let a is the acceleration of the object. It is given by :

a=\dfrac{dv}{dt}

a=\dfrac{d(6.8t)}{dt}

a=(6.8)\ m/s^2

So, the acceleration of the object is (6.8)\ m/s^2. Hence, this is the required solution.

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3 years ago
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