D= # of dimes
q= # of quarters
QUANTITY EQUATION:
d + q= 64
COST EQUATION:
0.10d + 0.25q= $9.25
STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2
(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40
STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q
Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40
0.15q= 2.85
divide both sides by 0.15
q= 19 quarters
STEP 3:
substitute q value in step 2 into either original equation to find d value
d + q= 64
d + 19= 64
subtract 19 from both sides
d= 45 dimes
CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25
ANSWER: There are 45 dimes and 19 quarters.
Hope this helps! :)
For the answer to the question above, we will use this formula to solve this problem
<span>d = kv^2 </span>
<span>plugging in, </span>
<span>4.2 = k*10^2 </span>
<span>k = 0.042 </span>
<span>d = 0.042v^2 </span>
<span>the revoised equation will be </span>
<span>d = 0.9*0.042v^2 , i.e. </span>
<span>d = 0.0378v^2
I hope my answer helped you</span>
Answer:
1 and 7/20 or in a decimal 1.35
Step-by-step explanation:
times the numerator and the denominator then simplify.
please mark me brainliest
Answer:
25 maybe
Step-by-step explanation:
