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konstantin123 [22]
3 years ago
15

What is an example of kinetic energy

Physics
1 answer:
Olenka [21]3 years ago
6 0

An airplane has a large amount of kinetic energy in flight due to its large mass and fast velocity.

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A 8.01-nC charge is located 1.87 m from a 4.50-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
valkas [14]

Answer:

Explanation:

Given

q_1=8.01\ nC

q_2=4.50\ nC

distance between the charges is given by d=1.87\ m

Electrostatic force between the charges is given by

F_{12}=F_{21}=\frac{kq_1q_2}{d^2}

where k=constant =9\times 10^{9}

F_{12}=F_{21}=\frac{9\times 10^9\times 8.01\times 4.50\times 10^{-18}}{(1.87)^2}

F_{12}=F_{21}=92.769\times 10^{-9}\ N

as both the charges are of similar nature therefore they repel each other

8 0
3 years ago
An arrow strikes a target moving at 75 m/s and embeds itself 15 cm into the target. If the arrow stopped with constant accelerat
zhenek [66]

Answer:

Answer:

4 ms

Explanation:

initial velocity, u = 75 m/s

final velocity, v = 0

distance, s = 15 cm = 0.15 m

Let the acceleration is a and the time taken is t.

Use third equation of motion

v² = u² + 2 a s

0 = 75 x 75 - 2 a x 0.15

a = - 18750 m/s^2

Use first equation of motion

v = u + at

0 = 75 - 18750 x t

t = 4 x 10^-3 s

t = 4 ms

thus, the time taken is 4 ms.

Explanation:

5 0
3 years ago
View this and help out??
Zina [86]
I would say b as well. I’m sorry if it’s wrong
5 0
3 years ago
Two identical mandolin strings under 200 N of tension are sounding tones with frequencies of 590 Hz. The peg of one string slips
Slav-nsk [51]

To solve this problem it is necessary to apply the concepts related to frequency and vibration of strings. Mathematically the frequency can be expressed as

f = \frac{v}{\lambda}

Then the relation between two different frequencies with same wavelength would be

\frac{f'}{f} = \frac{v'/\wavelength}{v/\wavelength}

\frac{f'}{f} = \frac{v'}{v}

The beat frequency heard when the two strings are sounded simultaneously is

f_{beat} = f-f'

f_{beat} = f(1-\frac{f'}{f})

f_{beat} = f(1-\frac{v'}{v})

We have the velocity of the transverse waves in stretched string as

v = \sqrt{\frac{T}{\mu}}

v = \sqrt{\frac{200N}{\mu}}

And,

v' = \sqrt{\frac{196N}{\mu}}

Therefore the relation between the two is,

\frac{v'}{v} = \sqrt{\frac{192}{200}}

\frac{v'}{v} = \sqrt{0.96}

Finally substituting this value at the frequency beat equation we have

f_{beat} = 590(1-\sqrt{0-96})

f_{beat} = 11.92Hz

Therefore the beats per second are 11.92Hz

4 0
2 years ago
You cross two pure tall (TT) plants with two pure short (tt) plants and produce four offspring. Which of the following statement
grandymaker [24]
All will have a dominant trait I can't see the following statments

4 0
2 years ago
Read 2 more answers
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