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ale4655 [162]
2 years ago
8

Question 5 of 20 Engineers are using computer models to study train collisions to design safer train cars. They start by modelin

g an elastic collision between two train cars traveling toward each other. Car 1 is traveling south at 18 m/s and has a full load, giving it a total mass of 14,650 kg. Car 2 is traveling north at 11 m/s and has a mass of 3,825 kg. After the collision car 1 has a final velocity of 6 m/s south. What is the final velocity of car 2? A. 81 m/s north O B. 81 m/s south C. 35 m/s south D. 35 m/s north​
Physics
2 answers:
Sonbull [250]2 years ago
8 0

Answer:

It's C

Explanation:

Your welcome!

aniked [119]2 years ago
6 0

Answer:

35m/s south

Explanation:

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Newton's laws of motion are true on earth and space.
frez [133]

Answer:

False

Explanation:

It is a common misunderstanding that objects in space have no weight. If that were true, they would just float away from the Earth, the Sun and the other planets. Objects in low Earth orbit experience about 90% of the weight that they feel on the surface of the Earth.

8 0
1 year ago
All of the members of a community belong to the same species tf
Anna35 [415]
That is false

I hope this helps!
3 0
3 years ago
How many photons are absorbed during the dental x-ray?
MariettaO [177]
<span>E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.

Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons </span>
8 0
2 years ago
A gold ball has a mass of 45g. In a speed test, a golf ball was driven from rest to a velocity of 90m/s.
Andrew [12]

Answer:

1)

Acceleration (a)=change in velocity/ change in time

Velocity (v)=90m/s

Time=0.0005s

a=90/0.0005

The acceleration =180000m/s^2 or 180km/s^2

Force = mass x acceleration

m=40g= 0.04kg

F= 0.04x 180000

F= 7200N or 7.2kN

Explanation:

7 0
3 years ago
A car’s 30.0-kg front tire is suspended by a spring with spring constant k=1.00x10^5 N/m. At what speed is the car moving if was
Taya2010 [7]

we know the equation for the period of oscillation in SHM is as follows:

T = 2 * pi * sqrt(mass/k)

we know f = 1/T, so f = 1/(2 * pi) * sqrt(k/m).

since d = v*T, we can say v = d/t = d * f

the final equation, after combining everything, is as follows:

v = d/(2 * pi) * sqrt(k/m)

by plugging everything in

v = .75/(2 * pi) * sqrt((1 * 10^5)/(30))

We find our velocity to be:

v = 6.89 m/s

6 0
3 years ago
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