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Pepsi [2]
3 years ago
11

50 POINTS ANSWER CORRECTLY

Physics
2 answers:
AveGali [126]3 years ago
8 0
I think its c 

Hope this is right
worty [1.4K]3 years ago
3 0
The answer would be B hope this helps :D
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(True or False Statement)
sertanlavr [38]
False is correct......
4 0
3 years ago
Particle 1 has mass 4.6 kg and is on the x-axis at x = 5.7 m. Particle 2 has mass 7.2 kg and is on the y-axis at y = 4.2 m. Part
Iteru [2.4K]

To solve this problem it is necessary to apply the concepts related to the Gravitational Force, for this purpose it is understood that the gravitational force is described as

F_g = \frac{Gm_1m_2}{r^2}

Where,

G = Gravitational Universal Force

m_i = Mass of each object

To solve this problem it is necessary to divide the gravitational force (x, y) into the required components and then use the tangent to find the angle generated between both components.

Our values are given as,

m_1 =4.6 kg\\m_2 = 7.2 kg\\m_3 = 2.6 kg\\r_1 = 5.7 m\\r_2 = 4.2 m

Applying the previous equation at X-Axis,

F_x = \frac{Gm_1m_3}{R_{1}^2}\\F_x = \frac{6.67*10^{-11}*4.6*2.6}{5.7^2}\\F_x = 2.46*10^{-11}N

Applying the previous equation at Y-Axis,

F_y = \frac{Gm_2m_3}{R_2^2}\\F_y = \frac{6.67*10^{-11}*7.2*2.6}{4.2^2}\\F_y = 7.08*10^{-11} N

Therefore the angle can be calculated as,

tan\theta = \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{7.08*10^{-11}}{2.46*10^{-11}}\\\theta = 71\°

Then in the measure contrary to the hands of the clock the Force in the particle 3 is in between the positive direction of the X and the negative direction of the Y at 71 ° from the positive x-axis.

5 0
4 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
3 years ago
Two boxes 100 kg and 200 kg are connected by a rope on a horizontal surface and are being pulled with a horizontal force of 500
crimeas [40]

Answer:

hope this helps you......

8 0
3 years ago
Oil of specific gravity 0.75 flows through a smooth contraction in a pipe at a volumetric flow rate of 3.2 cu ft / sec.Find the
pogonyaev

Answer:

The force required to hold the contraction in place is 665.91 N ↑

Explanation:

Given;

specific gravity of oil, γ = 0.75

Volumetric flow rate, V 3.2 Ft³/s = 0.0906 m³/s

\gamma =\frac{\rho_o}{\rho_w}

where;

\rho_o is the density of oil

\rho_w is the density of water = 1000 kg/m³

∴density of oil (\rho_o) = γ × density of water(\rho_w)

                               = 0.75 × 1000 kg/m³

                                = 750kg/m³

Buoyant Force = ρVg

                         = 750 × 0.0906 × 9.8

                         = 665.91 N ↑

This force acts upward or opposite gravitational force.

Therefore, the force required to hold the contraction in place is 665.91 N ↑

6 0
3 years ago
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