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Brut [27]
3 years ago
9

A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the

balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 5.3 m. The total mass of the empty balloon and basket is mb = 129 kg and the total volume is Vb = 0.057 m3. Assume the average person that gets into the balloon has a mass mp = 71 kg and volume Vp = 0.077 m3.1) What is the volume of helium in the balloon when fully inflated? m Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) What is the magnitude of the force of gravity on the entire system (but with no people)? Include the mass of the balloon, basket, and helium. N Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 3) What is the magnitude of the buoyant force on the entire system (but with no people)? Include the volume of the balloon, basket, and helium. N Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 4) What is the magnitude of the force of gravity on each person?
Physics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

Explanation:

1 ) the volume of helium in the balloon when fully inflated

= 4/3 π R³

= 4/3 x 3.14 x 5.3³

= 623.3 m³

2 ) force of gravity on the entire system ,but with no people

= (mass of the empty balloon and basket + mass of helium )x g

=( 129 +  623.3 x.18 )x 9.8

= 2363.7 N

3 )  magnitude of the buoyant force on the entire system (but with no people )

( Volume of empty balloon + basket + volume of helium ) density of air x g

( 0.057 + 623.3 ) x 1.23 x 9.8

= 7513.94 N

4 )  magnitude of the force of gravity on each person

Mass of each person x g

= 71 x 9.8

= 695.8 N

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Answer:

The student hears the wave that is transmitted by the desk

Explanation:

Mechanical waves need a material medium to be able to be transmitted, in the case of sound waves, one of the most common media is air, but it is also transmitted in other media in this case, stationery is transmitted.

The student hears the wave that is transmitted by the desk

The speed of the wave is proportional to the density of the material, so the wave that the student hears arrives much faster through the desk than through the air

6 0
3 years ago
"The International Space Station (ISS) orbits at a distance of 350 km above the surface of the Earth. (a) Determine the gravitat
vagabundo [1.1K]

Answer:

(a) g = 8.82158145m/s^2.

(b) 7699.990192m/s.

(c)5484.3301s = 1.5234 hours.(extremely fast).

Explanation:

(a) Strength of gravitational field 'g' by definition is

g = \frac{M_{(earth)} }{r^2} G , here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.

r = 6721,000 meters, putting this value in above equation gives g = 8.82158145m/s^2.

(b) We have to essentially calculate centripetal acceleration that equals new 'g'.

a_{centripetal}=\frac{V^2}{r} =g here g is known, r is known and v is unknown.

plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.

(c)  S = vT,  here T is time period or time required to complete one full revolution.

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solving for unknown gives T = 5484.3301s = 1.5234hours.

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3 years ago
The cornea behaves as a thin lens of focal lengthapproximately 1.80 {\rm cm}, although this varies a bit. The material of whichi
Keith_Richards [23]

Answer:

Explanation:

  a )

from lens makers formula

\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

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magnification = v / u

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= .776 mm

It will be a real image and it will be inverted.

 

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Following the Law of Conservation of Energy, energy cannot be destroyed nor created.

So you would do 75 N x 10m x Cos (0 degrees)= 750 J
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