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Brut [27]
3 years ago
9

A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the

balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 5.3 m. The total mass of the empty balloon and basket is mb = 129 kg and the total volume is Vb = 0.057 m3. Assume the average person that gets into the balloon has a mass mp = 71 kg and volume Vp = 0.077 m3.1) What is the volume of helium in the balloon when fully inflated? m Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2) What is the magnitude of the force of gravity on the entire system (but with no people)? Include the mass of the balloon, basket, and helium. N Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 3) What is the magnitude of the buoyant force on the entire system (but with no people)? Include the volume of the balloon, basket, and helium. N Submit You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 4) What is the magnitude of the force of gravity on each person?
Physics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

Explanation:

1 ) the volume of helium in the balloon when fully inflated

= 4/3 π R³

= 4/3 x 3.14 x 5.3³

= 623.3 m³

2 ) force of gravity on the entire system ,but with no people

= (mass of the empty balloon and basket + mass of helium )x g

=( 129 +  623.3 x.18 )x 9.8

= 2363.7 N

3 )  magnitude of the buoyant force on the entire system (but with no people )

( Volume of empty balloon + basket + volume of helium ) density of air x g

( 0.057 + 623.3 ) x 1.23 x 9.8

= 7513.94 N

4 )  magnitude of the force of gravity on each person

Mass of each person x g

= 71 x 9.8

= 695.8 N

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To solve this problem we will apply the concepts related to the electric field such as the smelting of the Force and the load (In this case the force is equivalent to the weight). Later we will apply the ratio of the total charge as a function of the multiplication of the number of electrons and their individual charge.

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5 0
4 years ago
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K = -½U

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Four point charges have equal magnitudes. Three are positive, and one is negative, as the drawing shows. They are fixed in place
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Ans= 9

See attached picture for clearer solution.

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The net electrostatic force acting on charge B = 2/2 + 2/(2)2 − 2/2 = 1/4 2/d2 .  

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The net electrostatic force acting on charge D = 2/2+ 2 /(2)2 + 2/(3)2 = 2 /2 (1 + 1/4 + 1/9 ) = 49/36 2/ 2 .  

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