Answer:
dmin = 1.4374in
Explanation:
In the question, it says slope at the support should not exceed the limit. When such a sentence is given always use the <u>maximum value of the property</u>. So here the maximum moment of inertia is used.
θ₁ = Pb(l² – b²)/6lEI
0.002 = 1000 x 8 x (142 - 82)/6 x 14 x 30 x 10⁶ x I₁
I₁ = 0.209523 in⁴
θ₂ = Pab(2l - b)/6lEI
0.002 = 1000 x 6 x 8 x (28 - 8)/6 x 14 x 30 x 10⁶ I2
I₂ = 0.190476 in⁴
<u>For design point of considerations, taking higher value of M.I, which is I₁</u>
I₁ = 0.209523 = (π/64) x d⁴
d⁴ = 4.2683
dmin = 1.4374in
Answer:
3.2 m
Explanation:
The equation to use to solve this problem is:

where
is the final velocity
is the initial velocity
a is the acceleration
is the distance covered
For the particle in free-fall in this problem, we have
(it starts from rest)

(acceleration due to gravity)
By re-arranging the equation, we can find the distance travelled:

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