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Ket [755]
3 years ago
5

In a thunderstorm, the formula: M = t 5.6 gives the approximate distance, M , in miles, from a lightning strike if it takes t se

conds to hear the thunder after seeing the lightning. If you are 7 miles away from the lightning flash, how long will it take the sound of the thunder to reach you.?
Physics
1 answer:
GrogVix [38]3 years ago
8 0

Answer:

t=1.25\,s

Explanation:

In a thunderstorm the lightening is seen first then the roar of the lightening is heard because of the fact that speed of the light is much greater than the speed of the sound.

Given that:

Relation   M=t\times 5.6

M= 7 miles

t=?

where:

t= time in seconds

M= distance in miles

Now,

Putting the given values in the relation above

7=t\times 5.6

t=1.25\,s

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Naily [24]

Answer:

I will answer in English.

Here we will use the relation

Velocity*time = distance

So:

a) velocity = 3m/s

time = 2s

Distance = 3m/s*2s = 6m

b) velocity = 2m/s

time = 3.5s

Distance = 2m/s*3.5s = 7m

c) velocity = 10m/s

time = 0.5s

Distance = 10m/s*0.5s = 5m

d) velocity = 4m/s

time = 2.5s

Distance = 4m/s*2.5s = 9m

e) velocity = 1.5m/s

time = 5s

Distance = 1.5m/s*5s = 7.5m

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3 years ago
A rabbit with a mass of 2.0 kg accelerates at 2.0 meters per second squared. Find the net force of the rabbit
scZoUnD [109]

Answer:

4N

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Given

Mass = 2.0kg

Acceleration = 2.0m/s^2

Force = 2.0 x 2.0

= 4N

5 0
4 years ago
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What is the speed, in m/s, of a wave on a cord if it has a wavelength of 4m and a period of 0.5 s
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sasho [114]
As a liquid is heated, its vapor pressure increases until the vapor pressure equals the pressure of the gas above it. ... In order to form vapor, the molecules of the liquid must overcome the forces of attraction between them. The temperature of a boiling liquid remains constant, even when more heat is added.
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3 years ago
Calculate the heat energy released when 13.3 g of liquid mercury at 25.00 C is converted to solid mercury at its melting point.C
dmitriy555 [2]

Answer:

-270.321012\ J

Explanation:

C_v = Heat capacity of Hg = 28 J/mol

\Delta T = Change in temperature = (234.32-(273.15+25))

\Delta H_{f} = Enthalpy of fusion = 2.29 kJ/mol

The number of moles is given by

n=13.3\times \dfrac{1}{200.59}\\\Rightarrow n=0.0663\ molHg

Heat is given by

Q_1=nC_v\Delta T\\\Rightarrow Q_1=0.0663\times 28\times (234.32-(273.15+25))\\\Rightarrow Q_1=-118.494012\ J

Heat released is given by

Q_2=-n\Delta H_{f}\\\Rightarrow Q_2=-0.0663\times 2.29\times 10^3\\\Rightarrow Q_2=-151.827\ J

Total heat is given by

Q=Q_1+Q_2\\\Rightarrow Q=-118.494012+(-151.827)\\\Rightarrow Q=-270.321012\ J

The total heat released is -270.321012\ J

4 0
3 years ago
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