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Ket [755]
3 years ago
5

In a thunderstorm, the formula: M = t 5.6 gives the approximate distance, M , in miles, from a lightning strike if it takes t se

conds to hear the thunder after seeing the lightning. If you are 7 miles away from the lightning flash, how long will it take the sound of the thunder to reach you.?
Physics
1 answer:
GrogVix [38]3 years ago
8 0

Answer:

t=1.25\,s

Explanation:

In a thunderstorm the lightening is seen first then the roar of the lightening is heard because of the fact that speed of the light is much greater than the speed of the sound.

Given that:

Relation   M=t\times 5.6

M= 7 miles

t=?

where:

t= time in seconds

M= distance in miles

Now,

Putting the given values in the relation above

7=t\times 5.6

t=1.25\,s

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The molecule that traps the sun's energy is ?.
kakasveta [241]
The molecule that trap's the sun's energy is chlorophyll.
7 0
3 years ago
An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on t
diamong [38]

Answer:

1. 18.5m/s

2. 17.5 m

3. 0 at its highest point

4. Direction is downwards

Explanation:

1. This egg is thrown vertically from a height

Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds

Y-Yo = V0t - 1/2gt²

-30-0 = V0(5)-1/2(9.8)(5²)

-30 = 5v0 - 4.9x25

-30 = 5V0 - 122.5

-30+122.4 = 5v0

V0 = 92.5/5

= 18.5m/s

<em><u>this </u></em><em><u>is </u></em><em><u>the </u></em><em><u>initial</u></em><em><u> </u></em><em><u>speed</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>egg</u></em>

2. When the egg is at a maximum height it would have a velocity equal to 0

V² = V0² - 2*g*y

V = 0, V0 = 18.5, g = 9.8

0 = 18.5²-2x9.8*y

342.25-19.6y = 0

342.25 = 19.6y

Divide through by 19.6

Y = 342.25/19.6

Y = 17.5m

<em><u>this value is how high it rises above starting point</u></em>

3.

The magnitude of velocity is = 0 at its highest point

4.

This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.

5. Please check attachment for graph

6 0
3 years ago
A glider of mass m1 on a frictionless horizontal track is connected to an object of mass m2 by a massless string. The glider acc
inysia [295]

Answer:

m2g -> T2 -> T1

Explanation:

m2g -> T2 -> T1

5 0
4 years ago
A horizontal circular platform (m = 119.1 kg, r = 3.23m) rotates about a frictionless vertical axle. A student (m = 54.3kg) walk
Murrr4er [49]

Answer:

\omega_2=5.1rad/s

Explanation:

Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is L=I\omega. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at r_2=1.39m from the center, then we have:

L_1=L_2

Or:

I_1\omega_1=I_2\omega_2

And we want to calculate:

\omega_2=\frac{I_1\omega_1}{I_2}

The total moment of inertia will be the sum of the moment of intertia of the disk of mass m_D=119.1 kg and radius r_D=3.23m, which is I_D=\frac{m_Dr_D^2}{2}, and the moment of intertia of the student of mass m_S=54.3kg at position r (which will be r_1=r=3.23m or r_2=1.39m) will be I_{S}=m_Sr_S^2, so we will have:

\omega_2=\frac{(I_D+I_{S1})\omega_1}{(I_D+I_{S2})}

or:

\omega_2=\frac{(\frac{m_Dr_D^2}{2}+m_Sr_{S1}^2)\omega_1}{(\frac{m_Dr_D^2}{2}+m_Sr_{S2}^2)}

which for our values is:

\omega_2=\frac{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(3.23m)^2)(3.1rad/s)}{(\frac{(119.1kg)(3.23m)^2}{2}+(54.3kg)(1.39m)^2)}=5.1rad/s

6 0
3 years ago
The length of a certain wire is doubled and at the same time its radius is also doubled. What is the new resistance of this wire
Leto [7]

Answer:

R' = R/2

Therefore, the new resistance of the wire is twice the value of the initial resistance.

Explanation:

Consider a wire with:

Resistance = R

Length = L

Area = A = πr²

where, r = radius

ρ = resistivity

Then:

R = ρL/A

R = ρL/πr²   --------------- equation 1

Now, the new wire has:

Resistance = R'

Resistivity = ρ

Length = L' = 2 L

Radius = r' = 2r

Area = πr'² = π(2r)² = 4πr²

Therefore,

R' = ρL'/πr'²

R' = ρ(2 L)/4πr²

R' = (1/2)(ρL/πr²)

using equation 1:

<u>R' = R/2</u>

<u>Therefore, the new resistance of the wire is twice the value of the initial resistance.</u>

4 0
3 years ago
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