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1 year ago

What is the force needed to accelerate a wagon with a mass of 10 kg at a rate

2 answers:

7 0

Any amount of force will do that given time.

The time to accelerate a 10kg object to 2m/s from rest using force F is:

t = mv/F = 20/F

Is there a typo?

Was the 2m/s written, a speed, supposed to be 2m/s 2
2
, an acceleration?

If so, then it takes 20N to accelerate a 10kg object by 2m/s 2
2

… from F = ma.

Mashutka [201]1 year ago

6 0

Answer:

Explanation:

Remember:

F = m * a

= 10 * 2 = 20 N

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Lava that cools so quickly that ions do not have time to arrange themselves into crystals will form igneous rocks with a _____ t

Alborosie

Lava cools so quickly that ions do not have time to arrange themselves into crystals will form igneous rocks with a glassy texture. Lava is the substance that flows from the volcano's.

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3 years ago

The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha

Anna007 [38]

Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

Height = 1.0 m

Time = 0.90 s

Let the mass of the other block is m.

We need to calculate the acceleration of each block

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$1.0=0+\dfrac{1}{2}\times a\times(0.90)^2$

$a=\dfrac{2\times1.0}{(0.90)^2}$

$a=2.46\ m/s^2$

We need to calculate the mass of the other block

Using newton's second law

The net force of the block M

$Ma=Mg-T$

$T=Mg-Ma$ ....(I)

The net force of the block m

$ma=T-mg$

Put the value of T from equation (I)

$ma=Mg-Ma-mg$

$m(a+g)=M(g-a)$

$m=\dfrac{M(g-a)}{(a+g)}$

Put the value into the formula

$m=\dfrac{100(9.8-2.46)}{2.46+9.8}$

$m=59.8\ \approx60\ kg$

Hence, The mass of the another block is 60 kg.

8 0

2 years ago

3. A 142 g baseball is thrown at a speed of 42.9 m/s. What is the kinetic energy of the baseball at this moment?

krok68 [10]

Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J

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2 years ago

How many joules of electrical energy is transferred per second by 6V 0.5 A lamp?

Degger [83]

When you ask for "joules per second", you're asking for "watts".
The rate of energy "transfer" is 'power'. In this case, the light bulb
transfers energy out of the electrical circuit and into the space
around it, in the form of light and heat radiation.

Electrical power = (voltage) x (current) =

(6 volts) x (0.5 ampere) =

3 watts = 3 joules per second.

4 0

2 years ago

To balance a chemical equation we use______. -coefficients -subscripts

Vitek1552 [10]

Answer:

Coefficients

Explanation:

Coefficients are used to balance chemical equations.
According to the law of conservation of mass, the mass of the reactants in a chemical equation should be equivalent to the mass of the products.
The conservation of mass is achieved in chemical equations is achieved through balancing chemical equations.
Balancing chemical equations is a try and error of putting appropriate coefficients to the reactants or products to ensure that the number of atoms of each element are equal on the side of the reactants and that of products.

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2 years ago