All categories

1 year ago

What is the force needed to accelerate a wagon with a mass of 10 kg at a rate

2 answers:

7 0

Any amount of force will do that given time.

The time to accelerate a 10kg object to 2m/s from rest using force F is:

t = mv/F = 20/F

Is there a typo?

Was the 2m/s written, a speed, supposed to be 2m/s 2
2
, an acceleration?

If so, then it takes 20N to accelerate a 10kg object by 2m/s 2
2

… from F = ma.

Mashutka [201]1 year ago

6 0

Answer:

Explanation:

Remember:

= 10 * 2 = 20 N

You might be interested in

How does this app work

ohaa [14]

Hello! ^^

Welcome to Brainly! Blah-blah

We are so excited, to meet you!

Brainly, is a website for you for answering questions, asking for help! if you need too. Plus, if you answer questions with explanation, you can also become a moderator in here too! But, you are not allow to answer d.umb questions on brainly... Plus, please be careful cause now there is scammers, on brainly... and they may give you a virus... So if you see a question in that don't press that link, just report...

And I hope you, will enjoy in brainly!

Have a great day!

#LearnWithBrainly

Answer:

Jace~

Plus, here is a anime image that might make your day happy. . .

6 0

2 years ago

An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1

Ksivusya [100]

<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

$F=\frac{GMm}{r^2}$

Where G = 6.67 x 10⁻¹¹ N m²/kg²

M = Mass of body 1

M = Mass of body 2

r = Distance between them

Here we have

M = Mass of Sun = 1.99×10³⁰ kg

m = Mass of asteroid = 4.00×10¹⁶ kg

F = 3.14×10¹³ N

Substituting

$F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m$

The asteroid is 4.11 x 10¹¹ m far from Sun

3 0

3 years ago

A particularly beautiful note reaching your ear from a rare Stradivarius violin has a wavelength of 39.1 cm. The room is slightl

USPshnik [31]

Given Information:

Wavelength = λ = 39.1 cm = 0.391 m

speed of sound = v = 344 m/s

linear density = μ = 0.660 g/m = 0.00066 kg/m

tension = T = 160 N

Required Information:

Length of the vibrating string = L = ?

Answer:

Length of the vibrating string = 0.28 m

Explanation:

The frequency of beautiful note is

f = v/λ

f = 344/0.391

f = 879.79 Hz

As we know, the speed of the wave is

v = √T/μ

v = √160/0.00066

v = 492.36 m/s

The wavelength of the string is

λ = v/f

λ = 492.36/879.79

λ = 0.5596 m

and finally the length of the vibrating string is

λ = 2L

L = λ/2

L = 0.5596/2

L = 0.28 m

Therefore, the vibrating section of the violin string is 0.28 m long.

3 0

2 years ago

Which is not an example of a scalar?

Crank

Answer:

b) 2ft/s

Explanation:

A scalar has only magintude, not direction

6.2m, 3kg, and -100 o C are all scalars because they only have magnitude.

2ft/s is not a scalar because it has a direction.

3 0

1 year ago

The diagram shows Ned’s movement as he left his house and traveled to different places throughout the day. Which reference point

aleksley [76]

The pet store would be the reference point because it is where he started and it will not move. Hope this helped.

6 0

2 years ago

Read 2 more answers