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PSYCHO15rus [73]
2 years ago
5

Atomic bombs send out a shock wave when they are detonated. This occurs because the bomb's detonation superheats the air particl

es nearby, which cause them to bump into other air particles that further the wave.
Physics
2 answers:
vova2212 [387]2 years ago
7 0

Question:

Atomic bombs send out a shock wave when they are detonated. this occurs because the bomb’s detonation superheats the air particles nearby, which cause them to bump into other air particles that further the wave.

which statement can most likely be made about the shock waves of atomic bombs?

a. they are a mechanical waves.

b. they are an electromagnetic waves.

c. they will act like x-rays.

d. they will act like light rays

Answer:

The correct option is;

a. they are a mechanical waves.

Explanation:

The shock waves of atomic bombs are mechanical waves which constitute the movement, back and forth, of particulate mater (oscillation), which results in energy (heat) transfer by means of a medium (air particles) over a distance.

As it is a longitudinal, mechanical wave, the motion of the air particles is in the direction of the wave and is limited to within the original region of the particle before the blast, maintaining as equilibrium position while transferring the energy to the adjacent neighboring air particle.

Dahasolnce [82]2 years ago
6 0

Answer:

That's right: The initial energy emission occurs by 80% or more in the form of gamma rays but these are quickly absorbed and dispersed mostly by air in little more than a microsecond, converting gamma radiation into thermal radiation (thermal pulse ) and kinetic energy (shock wave) which are actually the two dominant effects in the initial moments of the explosion. The rest of the energy is released in the form of delayed radiation (fallout or fallout) and is not always counted when measuring the performance of the explosion.

Explanation:

High altitude explosions produce greater damage and extreme radiation flux due to lower air density (photons encounter less opposition) and consequently a higher blast wave is generated.

For a long time before the invention of the bomb, some scientists believed that its detonation on the surface could cause the Earth's atmosphere to ignite, generating a global chain reaction in which nitrogen atoms would join together to form carbon and oxygen. This fact soon proved impossible since the densities necessary for these reactions to take place have to be much higher than atmospheric ones, and although there may be additional fusion reactions at the heart of the explosion, they do not provide enough energy to amplify and spreading the nuclear reaction to the rest of the atmosphere and the production of heavy elements ceases immediately. Regardless, this idea persists today as a misunderstanding rumor among many people.

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An astronaut has a mass of 75 kg and is floating in space 500 m from his 125,000 kg spacecraft. What will be the force of gravit
nikdorinn [45]

Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

1. Determination of the force of attraction.

Mass of astronaut (M₁) = 75 Kg

Mass of spacecraft (M₂) = 125000 Kg

Distance apart (r) = 500 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

F = 2.5×10¯⁹ N

Thus, the force of attraction between the astronaut and his spacecraft is 2.5×10¯⁹ N

2. Determination of the acceleration of the astronaut.

Mass of astronaut (m) = 75 Kg

Force (F) = 2.5×10¯⁹ N

Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

2.5×10¯⁹ N = 75 × a

Divide both side by 75

a = 2.5×10¯⁹ / 75

a = 3.33×10¯¹¹ m/s²

Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

5 0
2 years ago
A capacitor is charged until its stored energy is 7.54 J. A second capacitor is then connected to it in parallel. If the charge
Ivan

Answer:

2 J

Explanation:

A charged capacitor of capacitance C_1 with energy of 7.54 J, is connected in parallel with another capacitor C_2 , so the charge is equally distributed between them.

(a) The energy stored in the capacitor before it being connected to the other capacitor is:

U_O=q_0^2/2C_1=7.54 J\\

The energy stored in the electric field is the sum of the energies of the two capacitors:

U=U_1+U_2\\U=q_1^2/2C_1+q_2^2/2C_2

since the charge equally distributed,  q_1 = q_2 = q_o/2. and since they are connected in parallel the potential difference on both of them is the same :

V_1=V_2\\q_1/C_1=q_2/C_2\\q_0/C_1=q_0/C_2\\C_1=C_2=C_3\\

hence,

U=q_0^2/8C+q_0^2/8C\\U=q_0^2/4C\\U=2J

8 0
3 years ago
A flat uniform circular disk (r= 2.00m,
dusya [7]

Incomplete question.The Complete question is here

A flat uniform circular disk (radius = 2.00 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a friction less axis perpendicular to the center of the disk. A 40.0-kg person, standing 1.25 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.00 m/s relative to the ground.

a.) Find the resulting angular speed of the disk (in rad/s) and describe the direction of the rotation.

b.) Determine the time it takes for a spot marking the starting point to pass again beneath the runner's feet.

Answer:

(a)ω = 1 rad/s

(b)t = 2.41 s

Explanation:

(a) initial angular momentum = final angular momentum  

0 = L for disk + L............... for runner

0 = Iω² - mv²r ...................they're opposite in direction

0 = (MR²/2)(ω²) - mv²r ................where is ω is angular speed which is required in part (a) of question

0 = [(1.00×10²kg)(2.00 m)² / 2](ω²) - (40.0 kg)(2.00 m/s)²(1.25 m)

0=200ω²-200

200=200ω²

ω = 1 rad/s

b.)

lets assume the "starting point" is a point marked on the disk.

The person's angular speed is  

v/r = (2.00 m/s) / (1.25 m) = 1.6 rad/s

As the person and the disk are moving in opposite directions, the person will run part of a revolution and the turning disk would complete the whole revolution.

(angle) + (angle disk turns) = 2π

(1.6 rad/s)(t) + ωt = 2π

t[1.6 rad/s + 1 rad/s] = 2π

t = 2.41 s

6 0
3 years ago
What are 3 ways a car can accelerate? (CRE)
Nookie1986 [14]
Answer - There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.
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3 years ago
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A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0
Mamont248 [21]

Answer:

|P_3|=21.242m/s

Explanation:

From the question we are told that:

Mass m=200g=0.2

Speed v=82.0m/s

Mass M_2=300g=0.3kg

Speed V_2=45.0m/s

Generally the equation for Magnitude of the Third piece is mathematically given by

P_1+P_2+P_3=0

|P_3|=|P_1+P_2|

Where

P_1=m_1v_1

P_1=0.2*82

P_1=16.4kgm/s

And

P_2=0.3*45

P_2=13.5kgm/s

Therefore

|P_3|=\sqrt{16.4^2+13.5^2}

|P_3|=21.242m/s

8 0
3 years ago
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