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Pepsi [2]
3 years ago
10

How do the early efforts of women during the suffrage movement compare to the later years

Physics
1 answer:
Nat2105 [25]3 years ago
7 0

The idea that women's liberation is also men's liberation arouses the awakening of feminism. In 1966 Frieden and other feminists founded the National Organization for Women. Then other women's organizations for equal rights were formed in the United States and Western Europe. These organizations sought to overturn discriminatory laws and practices that forced women to hold down their status, such as discrimination in matters of contract and property ownership, employment and wages, the treatment of wage income, and issues relating to sex and child-bearing. The growing feminist movement more broadly seeks to change social stereotypes that women are more vulnerable, passive and dependent, less rational and emotionally reactive than men. Feminism strives for greater freedom for women in the workplace and makes them financially and psychologically independent of men, if they wish. Feminists criticized society's general emphasis on women as objects of sexual desire and sought to raise women's awareness and expand their opportunities in order to achieve equality with men. Another objective of feminism is to promote women's participation in all areas of political decision-making and social life.

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eimsori [14]

Answer:

inertia

Explanation:

7 0
3 years ago
A 160.-kilogram space vehicle is traveling along a straight line at a constant speed of 800. Meters per second. The magnitude of
natulia [17]

Answer:

Zero

Explanation:

As force acting on the body is equal to the product of mass and acceleration.

Acceleration is equal to rate of change in velocity.

Here velocity is constant so acceleration is zero.

It means the net force acting on the vehicle is zero.

4 0
3 years ago
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An airplane is flying through a thundercloud at a height of 2 000 m. (this is a very dangerous thing to do because of updrafts,
tester [92]
It is given that an<span> airplane is flying through a thundercloud at a height of 2000 m.
</span><span>
Since the parity of charges is opposite and the airplane lies between the two charges and both the electric fields are in the same direction at the plane. Therefore, the magnitudes of the electric field at the aircrafts will add up.
Now, check the image to see the calculations:

</span>

4 0
3 years ago
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Two particles A and B start simultaneously from a Point P with velocities 20 m/s and 30 m/s respectively. A and B move with acce
zysi [14]

Answer:

<u>20 m/s</u>

Explanation:

<u>Given</u>

  • u(A) = 20 m/s
  • u(B) = 30 m/s
  • acceleration equal in magnitude but opposite in direction

<u>Solving</u>

  • Velocity of A at Q = 30 m/s
  • From, P to Q, <u>Δv(A) = 30 - 20 = +10 m/s</u>
  • Therefore, velocity of B at Q will be decreased by 10 as it is equal in magnitude but opposite in direction to A
  • Δv(B) = v(B at Q) - u(B at P)
  • -10 m/s = v(B at Q) - 30 m/s
  • v(B at Q) = 30 - 10 = <u>20 m/s</u>
6 0
3 years ago
One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe
Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

\mu = \frac{m}{l}

\mu = \frac{8.79*10^{-3}}{70*10^{-2}}

\mu = 0.01255kg/m

The expression for the wavelength of the standing wave for the second overtone is

\lambda = \frac{2}{3} l

Replacing we have

\lambda = \frac{2}{3} (70*10^{-2})

\lambda = 0.466m

The frequency of the sound wave is

f_s = \frac{v}{\lambda_s}

f_s = \frac{344}{0.768}

f_s = 448Hz

Now the velocity of the wave would be

v = f_s \lambda

v = (448)(0.466)

v = 208.768m/s

The expression that relates the velocity of the wave, tension on the string and linear mass density is

v = \sqrt{\frac{T}{\mu}}

v^2 = \frac{T}{\mu}

T= \mu v^2

T = (0.01255kg/m)(208.768m/s)^2

T = 547N

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the n^{th} harmonic frequency is

f_n = nf_1

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

n=3

Then,

f_3 = 3f_1

Rearranging to find the fundamental frequency

f_1 = \frac{f_3}{3}

f_1 = \frac{448Hz}{3}

f_1 = 149.9Hz

7 0
3 years ago
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