Answer:
Increase his activity and exercise levels and add more calories to gradually gain weight
Explanation:
The hot gases produce their own characteristic pattern of spectral lines, which remain fixed as the temperature increases moderately.
<h3><u>Explanation: </u></h3>
A continuous light spectrum emitted by excited atoms of a hot gas with dark spaces in between due to scattered light of specific wavelengths is termed as an atomic spectrum. A hot gas has excited electrons and produces an emission spectrum; the scattered light forming dark bands are called spectral lines.
Fraunhofer closely observed sunlight by expanding the spectrum and a huge number of dark spectral lines were seen. "Robert Bunsen and Gustav Kirchhoff" discovered that when certain chemicals were burnt using a Bunsen burner, atomic spectra with spectral lines were seen. Atomic spectral pattern is thus a unique characteristic of any gas and can be used to independently identify presence of elements.
The spectrum change does not depend greatly on increasing temperatures and hence no significant change is observed in the emitted spectrum with moderate increase in temperature.
Answer:
22.11 m / s
Explanation:
The falcon catches the prey from behind means both are flying in the same direction ( suppose towards the left )
initial velocity of falcon = 28 cos 35 i - 28 sin 35 j
( falcon was flying in south east direction making 35 degree from the east )
momentum = .9 ( 28 cos 35 i - 28 sin 35 j )
= 20.64 i - 14.45 j
initial velocity of pigeon
= 7 i
initial momentum = .325 x 7i
= 2.275 i
If final velocity of composite mass of falcon and pigeon be V
Applying law of conservation of momentum
( .9 + .325) V = 20.64 i - 14.45 j +2.275 i
V = ( 22.915 i - 14.45 j ) / 1.225
= 18.70 i - 11.8 j
magnitude of V
= √ [ (18.7 )² + ( 11.8 )²]
= 22.11 m / s
Explanation:
If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :
F = q E
Hence, this is the required solution.
