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Llana [10]
2 years ago
13

What is the formula to find the second charge in Coulomb's Law?

Physics
2 answers:
kicyunya [14]2 years ago
5 0

Answer:

1.F is the electrostatic force between charges (in Newtons),

2.q₁ is the magnitude of the first charge (in Coulombs),

3.q₂ is the magnitude of the second charge (in Coulombs),

4.r is the shortest distance between the charges (in m),

5.ke is the Coulomb's constant. It is equal to 8.98755 × 10⁹ N·m²/C² .

crimeas [40]2 years ago
4 0

Explanation:

F is the electrostatic force between charges (in Newtons), 2. q, is the magnitude of the first charge (in Coulombs), 3. q2 is the magnitude of the second charge (in Coulombs), 4. r is the shortest distance between the charges (in m), 5. ke is the Coulomb's constant. It is equal to 8.98755 × 10⁹ N-m²/C².

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Answer:

(a) W = 1329.5 J = 1.33 KJ

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Explanation:

(a)

Work done by the gas can be found by the following formula:

W = P\Delta V

where,

W = Work = ?

P = constant pressure = (0.991 atm)(\frac{101325\ Pa}{1\ atm}) = 100413 Pa

ΔV = Change in Volume = 18.7 L - 5.46 L = (13.24 L)(\frac{0.001\ m^3}{1\ L}) = 0.01324 m³

Therefore,

W = (100413 Pa)(0.01324 m³)

<u>W = 1329.5 J = 1.33 KJ</u>

<u></u>

(b)

Using the first law of thermodynamics:

ΔU = ΔQ - W (negative W for the work done by the system)

where,

ΔU = change in internal energy of the gas = ?

ΔQ = heat added to the system = 25.6 KJ

Therefore,

ΔU = 25.6 KJ - 1.33 KJ

<u>ΔU = 24.27 KJ</u>

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