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2 years ago

Why do high and low tides happen 1 hour later each day? just answer please and it is a written response

1 answer:

6 0

With each passing day, the high tides occur about an hour later. The moon rises about an hour later each day, too (actually, 54 minutes later). Since the moon pulls up the tides, these two delays are connected. As the earth rotates through one day, the moon moves in its orbit.

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A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?

Andrei [34K]

The gravitational constant (G) in its base SI units is

3/2
m
3
k
g
/
s
2

But is often seen written as

⋅
N
⋅
2/2
m
2
/
k
g
2

Where N is the Newton unit. N=kg ⋅
⋅
m/s 2
2

4 0

1 year ago

You throw a rock straight up into the air with a speed of 14.2 m/s. how long does it take the rock to reach its highest point?

slega [8]

The acceleration of gravity on or near the Earth's surface is 9.8 m/s² downward.
Is that right ? I don't hear any objection, so I'll assume that it is.

That means that during every second that gravity is the only force on an object,
the object either gains 9.8m/s of downward speed, or it loses 9.8m/s of upward
speed. (The same thing.)

If the rock starts out going up at 14.2 m/s, and loses 9.8 m/s of upward speed
every second, it runs out of upward gas in (14.2/9.8) = 1.449 seconds (rounded)

At that point, since it has no more upward speed, it can't go any higher. Right ?

(crickets . . .)

4 0

2 years ago

Which circuit would have the most electrical power?

aliya0001 [1]

the answer is c because it has the most volts

6 0

1 year ago

What net force acting on a 14 KG wagon produces an acceleration of 1.5 MS^2?

valentina_108 [34]

21N

Explanation:

Given parameters:

Mass of wagon = 14kg

Acceleration = 1.5m/s²

Unknown:

Net force on wagon = ?

Solution:

Force is a pull or push on a body that causes a body to change its state. It is expressed as:

Force = mass x acceleration

Force on wagon = 14 x 1.5 = 21N

Learn more:

Force brainly.com/question/10470406

#learnwithBrainly

7 0

2 years ago

A ball is launched from ground level at 20 m/s at an angle of 40° above the

DedPeter [7]

(a) The ball's height y at time t is given by

y = (20 m/s) sin(40º) t - 1/2 g t ²

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve y = 0 for t :

0 = (20 m/s) sin(40º) t - 1/2 g t ²

0 = t ((20 m/s) sin(40º) - 1/2 g t )

t = 0 or (20 m/s) sin(40º) - 1/2 g t = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 g t

t = (40 m/s) sin(40º) / g

t ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration g. So

0² - ((20 m/s) sin(40º))² = 2 (-g) y

where y in this equation refers to the maximum height of the ball. Solve for y :

y = ((20 m/s) sin(40º))² / (2g)

y ≈ 8.4 m

8 0

2 years ago