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Yanka [14]
3 years ago
8

What would be the current of the same wire if it was moved up towards the magnet instead of through the magnetic field?

Physics
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

0 v

Explanation:

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Why might measuring changes in speed or direction be important?
aliya0001 [1]
It’s important because if you were let’s say training to see how far you go in 10sec you need to record your data to see how much you are improving in that skill or something
5 0
3 years ago
Two inductors, L1 and L2, are in parallel. L1 has a value of 25 mH and L2 a value of 50 mH. The parallel combination is in serie
Bond [772]

Answer:

Explanation:

For parallel inductors ,

\frac{1}{L_R} = \frac{1}{L_1} +\frac{1}{L_2}

\frac{1}{L_R} =\frac{1}{25} +\frac{1}{50}

L_R=16.67 mH.

For series combination

Total inductance

= 16.67 + 20

= 36.67 mH .

reactance of total inductance at 300 kHz

= ωL_{total} where ω is angular frequency

= 2πfL_{total}

= 2 x 3.14 x 300 x 10³ x 36.67 x 10⁻³

= 69.1 x 10³ ohm

Total rms current = Vrms / reactance

= 60 / 69.1 x 10³ A

= .87 x 10⁻³ A

= .87 mA

7 0
3 years ago
How much energy is needed to generate 0.71 x 10-16 kg of mass?
AleksAgata [21]

Answer:

6.39 J of energy is needed to generate 0.71 * 10⁻¹⁶ kg mass

Explanation:

According to the Equation: E = mc²

where the mass, m = 0.71 * 10⁻¹⁶ kg

the speed of light, c = 3 * 10⁸ m/s

The amount of energy needed to generate a mass of 0.71 * 10⁻¹⁶ kg is calculated as follows:

E = (0.71 * 10⁻¹⁶) (3 * 10⁸)²

E = 0.71 * 10⁻¹⁶ * 9 * 10¹⁶

E = 0.71 * 9

E = 6.39 J

6 0
3 years ago
The current in two identical light bulbs connected in series is 0. 25 A. The voltage across both bulbs is 110 V. The resistance
konstantin123 [22]

Answer:

220 ohms

Explanation:

I = V / R

0.25 = 110 / R

R = 110 / 0.25

R = 440 ohms

Equivalent resistance = 440 ohms

Resistance of single light bulb = Equivalent resistance / number of bulbs

= 440 / 2

= 220 ohms

8 0
2 years ago
A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

5 0
3 years ago
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