Answer:
Part A:
Time taken by the snake to reach its top speed is 1.28571 sec.
Part B:
Snake travels 2.0828 m in that time
Part C:
Mongoose have a chance to catch the black mamba
Explanation:
Part A:
According to first equation of motion:
v_f is top speed
v_i is initial or minimum speed
t is time
a is acceleration
Time taken by the snake to reach its top speed is 1.28571 sec
Part B:
According to Second equation of motion:
v_i=0
Snake travels 2.0828 m in that time
Part C:
Distance covered by black mamba is 2.0828 m which is less than its length 3.12 m
2.0828 m<3.12 m
Mongoose have a chance to catch the black mamba
GivenG=25,lg=10mA=10×10 power by 3A,v=100V
To find resistance(Rs)
Formula R
′
s=
lg−G
V
Calculations by formula
R
′
s=
(10×10
−3
−25
100
=10000−25
=9975
Ans- resistance by 9975Ω
Answer:
Each jump covers one center of the square to the other. If you can imagine the scenario, a single jump would cover a length of the side of one whole square. So, if it took three jumps, the total distance would be
d = 3 * 5 cm
d = 15 cm
Therefore, the magnitude or distance is 15 cm. The displacement depends on the direction of motion.
Answer:
a. 0.18Hz
b. 0.56m/s
Explanation:
From the question we can deduct the following parameters
The wavelength, λ is define as the distance between two successful crest or trough and from the question we conclude that wavelength is 3.17m.
Also the period of the wave T can be computed as
T=22.6/4
T=5.65secs.
a. To compute the frequency, recall that frequency, F=1/period.
Hence,
F=1/5.65
F=0.18Hz
b. Next we compute the wave speed.
Wave speed=frequency *wavelength
Wave speed =0.18*3.17
Wave speed =0.56m/s
Explanation:
here's the answer
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