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Physics

2 answers:

Ede4ka [16]3 years ago

7 0

<h3>Further explanation</h3>

Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

<h3>sin ∠A = opposite / hypotenuse</h3><h3>cos ∠A = adjacent / hypotenuse</h3><h3>tan ∠A = opposite / adjacent </h3>

There are several trigonometric identities that need to be recalled, i.e.

$cosec ~ A = \frac{1}{sin ~ A}$

$sec ~ A = \frac{1}{cos ~ A}$

$cot ~ A = \frac{1}{tan ~ A}$

$tan ~ A = \frac{sin ~ A}{cos ~ A}$

Let us now tackle the problem!

If sec (y) = 25/24 , then we can assume that :

adjacent side = 24 cm

hypotenuse = 25 cm

opposite side = $\sqrt{25^2 - 24^2}$ = $7 ~ cm$

sin (y) = opposite / hypotenuse = $7/25$

If sin (x) = 1/3 , then we can assume that :

opposite side = 1 cm

hypotenuse = 3 cm

adjacent side = $\sqrt{3^2 - 1^2}$ = $\sqrt{8} ~ cm$

cos (x) = adjacent / hypotenuse = $\sqrt{8}/3$ = $\frac{2\sqrt{2}}{3}$

$\sin (x + y) = \sin x ~ \cos y + \cos x ~ \sin y$

$\sin (x + y) = \frac{1}{3} \times \frac{24}{25} + \frac{2\sqrt{2}}{3} \times \frac{7}{25}$

$\large {\boxed {\sin (x + y) = \frac{24 + 14\sqrt{2}}{75} \approx 0.58} }$

<h3>Learn more</h3>

Calculate Angle in Triangle : brainly.com/question/12438587
Periodic Functions and Trigonometry : brainly.com/question/9718382
Trigonometry Formula : brainly.com/question/12668178

<h3>Answer details</h3>

Grade: College

Subject: Mathematics

Chapter: Trigonometry

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

Blizzard [7]3 years ago

6 0

We can approach this in another way.
We know that sin(∅) = height / hypotenuse.

Thus, for x, height is 1 and hypotenuse is 3. Using Pythagoras theorem,
3² = 1² + b²
b = √8
cos(x) = b/hypotenuse
cos(x) = √8 / 3

Now, lets consider y:
sec(y) = 1 / cos(y) = 1 / base / hypotenuse = hypotenuse / base
The hypotenuse is 25 and the base is 24. We again apply Pythagoras theorem to find the third side, which works out to be:
height = 7
sin(y) = height / hypotenuse
sin(y) = 7/25

Now, sin(x + y) =
sin(x)cos(y) + sin(y)cos(x)
= (1/3)(24/25) + (√8 / 3)(7/25)
= 8/25 + 7√8/75
= (24 + 14√2) / 75

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