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nataly862011 [7]
4 years ago
15

How to calculate the area of a triangle??

Mathematics
2 answers:
inessss [21]4 years ago
6 0

1/2 Baseb X Height.. Hope I helped.

Artemon [7]4 years ago
5 0

1/2base×height ====> is how you do this properly

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Express the following pattern as an algebraic expression: 88, 75, 62, 49. Use “n” for the term number.
Ostrovityanka [42]

Answer:

-13n + 101

Step-by-step explanation:

88, 75, 62, 49. = -13  -13 -13 = -13n + 101  (as 88+13 = 101)

5 0
3 years ago
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A conjecture and the two-column proof used to prove the conjecture are shown. Given: S is the midpoint of segment R T. Segment R
Scrat [10]

given: s is the midpoint of rt

definition of midpoint: rs st

given: st xy

transitive property of congruence: rs xy

6 0
3 years ago
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Chen bought a 20-foot chain for $36.50. What is the unit rate of price per foot?
jasenka [17]
About 1.83. You would set up the equation like this
3 0
2 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
The sum of a number and three is doubled and then added to the product of six and the original number to give forty six
Zina [86]

Answer:

The number is 5

Step-by-step explanation:

Let x represent the number

Now let's break it down!

Sum of a number and 3 gives;

x + 3

This is then doubled to give;

2* (x + 3)

This is added to the product of 6 and the original number to give 46

Product of 6 and the original number = 6 * x

Now 2* (x + 3) is added to 6 * x to give 46

2* (x + 3) + 6*x = 46

2x + 6 + 6x = 46

8x + 6 = 46

Subtract 6 from both sides

8x + 6 - 6 = 46 - 6

8x = 40

x = 40/8

x = 5

Hence, the number is 5

3 0
3 years ago
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