We know that the sum of all angle measures in a trapezoid is 360* (* means degrees)

Therefore we can construct the equation
(X+28)+(x)+(4x-14)+(4x-14)= 360

Now add like terms

10x = 360

And divide by the coefficient of X (aka 10)

X= 36

7 0

3 years ago

Please help me....I really need help!!

scoundrel [369]

$\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}$

6 0

3 years ago

The scale on a map is 55 cm: 88 km. If the distance between two cities is 5656 km, how far apart in cm are the two cities on the

Alinara [238K]

Answer:

3,535 cm

Step-by-step explanation:

55cm=88km

Let's make that "one unit" - 55cm=1 unit. How many units are in the distance 5656km?

5656km/88km=64.2727... units.

55cmx64.2727... = 3,534.999 cm (depending on what your teacher requires, we can probably round to 3,535).

Therefore, we know that the two cities are 3,535 cm apart on the map.

6 0

2 years ago

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