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olasank [31]
3 years ago
5

Facts about light years

Physics
2 answers:
Westkost [7]3 years ago
5 0
I learn this in school a light years is how fast light can tralw in space  i do not know how to spell that word
Anton [14]3 years ago
4 0
 A light-year is how astronomers measure distance in space.
-Light can travel 300,000 kilometres in one seconds!
Light year is the distance that light travel can travel in one year.
-Light can also travel 9,00,000,000,000 kilometers.
-One light is about 10 trillion km.
-Almost 300 years ago ,a Danish scientist named olaus roemer,was the fist man to estimate the distance light travels in a year -and using that he figure out the approximate speed of light!
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Answer:

The electric force is  F =  11.9 *10^{-9} \ N

Explanation:

From the question we are told that

    The  Bohr radius at ground state is  a_o  =  0.529 A =  0.529 ^10^{-10} \ m

    The values of the distance between the proton and an electron  z =  2.63a_o

The electric force is mathematically represented as

     F  =  \frac{k * n  * p }{r^2}

Where n and p are charges on a single electron and on a single proton which is mathematically represented as

      n = p  =   1.60 * 10^{-19} \ C

    and  k is the coulomb's  constant with a value

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substituting values

       F =  \frac{9*10^{9} *  [(1.60*10^{-19} ]^2)}{(2.63 * 0.529 * 10^{-10})^2}

         F =  11.9 *10^{-9} \ N

     

3 0
3 years ago
A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
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Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

(m1v1)i + (m2v2)i = (m1v1)f + (m2v2)f

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V2f = 11.33 m/s

<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>

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2 years ago
Help!! <br> A. 0.5 s <br> B. 1.0 s<br> C. 1.5 s<br> D. 2.0 s
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Answer:

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Explanation:

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A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis
Natali5045456 [20]

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

M_{before} = M_{after}

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

(m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

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