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mario62 [17]
3 years ago
5

Help me with number 28.

Physics
1 answer:
Ray Of Light [21]3 years ago
3 0
What you wrote in the space under the question is correct, but
you can go a lot farther than that.

The question gives you the mass of the object, and enough information
to calculate its volume. 

So go on from where you left off ... take the formula you wrote (correctly),
plug in the numbers for mass and volume, and find the density.  You can do it !
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The total yearly world consumption of energy is approximately 4.0 × 1020 J. How much mass would have to be completely converted
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Read 2 more answers
cylindrical container is to be constructed to be open at the top with a volume of 27π cubic meters using the least amount of mat
Llana [10]

Answer:

radius comes out to be 3 m

height of the cylinder comes out to be 3m

Explanation:

given

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π r² h = 27π

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surface area of cylinder open at the top

S = 2πrh + π r²

S = 2\pi \dfrac{27}{r} + \pi r^2

\frac{\mathrm{d} s}{\mathrm{d} r}=\frac{\mathrm{d}}{\mathrm{d} r} (2\pi \dfrac{27}{r} + \pi r^2)

\frac{\mathrm{d} s}{\mathrm{d} r}=54\pi \dfrac{-1}{r^2}+2\pi r

\frac{\mathrm{d} s}{\mathrm{d} r}=0

for least amount of material requirement.

\dfrac{54\pi }{r^2} = 2\pi r\\r=3m

hence radius comes out to be 3 m

for height put the value in the equation 1

so, height of the cylinder comes out to be 3m

3 0
3 years ago
Read 2 more answers
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