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yawa3891 [41]
3 years ago
9

What is the empirical formula for Hg2(NO3)2

Chemistry
1 answer:
natima [27]3 years ago
5 0
<span>I think it's HgNO3 because the subscripts on Hg and No3 are divisible by 2  :)
</span>
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Name two metals alloyed with iron to make stainless steel.
kirill115 [55]
For stainless steel different kinds of compositions are used. Based on that different series of stainless steel has been coined.
1. Series 200 - Iron alloyed with <span>chromium, nickel and manganese.
2. Series 300 - It has 
a. Stainless Steel 304 - it has composition of 18% chromium and 8% Nickel
b. </span>Stainless Steel 316 - This has 18% chromium and 10% Nickel

Each kind of stainless steel is of different cost and has different applications.
7 0
3 years ago
Which lists mixtures, in order, from the smallest particles to the largest particles?
Kisachek [45]

Answer:

A. Solution, Colloid, Suspension

Hope i could help

4 0
3 years ago
Convert 4.992×1010 g to each of the following units.<br> B. Mg<br> c. mg<br> D. metric tons
SVETLANKA909090 [29]
I think it is letter D
3 0
3 years ago
A reaction is followed and found to have a rate constant of 3.36 × 104 m-1s-1 at 344 k and a rate constant of 7.69 m-1s-1 at 219
g100num [7]

The relation between rate constants at different temperatures, temperature and activation energy is known as Arrhenius equation

<u>Arrhenius equation</u>

K=Ae^-{\frac{Ea}{RT} }

For two temperatures

Ea=R(\frac{ln\frac{k1}{k1} }{(\frac{1}{T1})-(\frac{1}{T2})})

Where

Ea = ? = activation energy

k1 = 3.36 × 10⁴

T1=344 k

k2=7.69

T2=219K

R= gas constant = 8.314 J /molK

Putting values

Ea= (8.314)(\frac{ln(\frac{7.69}{33600})}{(\frac{1}{344})(\frac{1}{219})}

Ea = (-69.69)/(-0.00166) = 41981.93 J/mol

Or

Activation energy is 42.0 kJ /mol

3 0
3 years ago
NEED HELP ASAP! PLEASE!
pshichka [43]

Answer: B.) Ionic

Explanation: It is B because it is the type of bond that is most likely being presented in row 1.

8 0
2 years ago
Read 2 more answers
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