Answer:
A. Along warm-water currents from warmer regions to colder regions
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Explanation:
When silver ionizes, it donates one electron. A neutral Ag atom has 47 electrons. When it ionizes, it becomes 46. The electronic configuration becomes: [Kr]5s¹4d⁹. Thus, the quantum numbers are:
<em>n = 1,2,3,4,5</em>
<em>l = 0,1,2,3,4 || (0 to n-1)</em>
<em>ml = -4,-3,-2,-1,0,1,2,3,4 || (-l to +l)</em>
<em>ms = +1, -1 </em>
Let (NO2)n be the molecular formula,
(14+16x2)n=138.02
n=3
molecular formula: (NO2)3=N3O6
The scenario whereby the initial pressure is equal to the final pressure is : ( A ) A balloon filled with air is heated from 300k to 600k, causing it to expand and double in size.
<h3>Gay Lussac's law </h3>
Gay Lussac's law states that at constant pressure, the volume of gas is directly proportional to the change in temperature. i.e. V ∝ T. From scenario 1 the change in temperature from 300 K to 600 K shows a 100% increase in temperature which corresponds with the expansion and size doubling of the volume of gas.
Hence we can conclude that The scenario whereby the initial pressure is equal to the final pressure is : ( A ) A balloon filled with air is heated from 300k to 600k, causing it to expand and double in size.
Learn more about Gay Lussac's law : brainly.com/question/24691513
The isotope that is more abundant, given the data is isotope Li7
<h3>Assumption</h3>
- Let Li6 be isotope A
- Let Li7 be isotope B
<h3>How to determine whiche isotope is more abundant</h3>
- Molar mass of isotope A (Li6) = 6.02 u
- Molar mass of isotope B (Li7) = 7.02 u
- Atomic mass of lithium = 6.94 u
- Abundance of A = A%
- Abundance of B = (100 - A)%
Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]
6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]
6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]
6.94 = [6.02A% + 702 - 7.02A%] / 100
Cross multiply
6.02A% + 702 - 7.02A% = 6.94 × 100
6.02A% + 702 - 7.02A% = 694
Collect like terms
6.02A% - 7.02A% = 694 - 702
-A% = -8
A% = 8%
Thus,
Abundance of B = (100 - A)%
Abundance of B = (100 - 8)%
Abundance of B = 92%
SUMMARY
- Abundance of A (Li6) = 8%
- Abundance of B (Li7) = 92%
From the above, isotope Li7 is more abundant.
Learn more about isotope:
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