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arsen [322]
3 years ago
6

For a particular lab experiment, you need 150 mL of a 2.50 M solution of ammonium nitrate. How many grams of NH4NO3 will you nee

d for the solution?
8.0 g

10.02 g

25.0 g

875.0 g

30.0 g
Chemistry
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

mass NH4NO3 = 30.0 g

Explanation:

∴ V = 150 mL

∴<em> C</em> NH4NO3 = 2.50 M

⇒ mass NH4NO3 = ?

∴ mol NH4NO3 = (0.150 L)×(2.50 mol/L) = 0.375 mol NH4NO3

∴ Mw NH4NO3 = 80.043 g/mol

⇒ mass NH4NO3 = (0.375 mol)×(80.043 g/mol) = 30.016 g

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