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tino4ka555 [31]
3 years ago
12

PLEASE I NEED HELP!!!!!!!!!!!!! I AM GIVING THE HIGHEST POINTS POSSIBLE! PLEASE, I AM FAILING, I JUST NEED HELP!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!
suppose you found a fossil of a clamshell. What can you conclude about the once-living organism and how it became a fossil?
Chemistry
2 answers:
NikAS [45]3 years ago
5 0

The organism was once a clam and most likely became a fossil after being buried by silt in its watery environment after death. Might need more clarification on what exact answer you need.

Vinvika [58]3 years ago
4 0

You already know what type of fossil it is. It is a sea animal which means you already know the general location of the animal which would of been the beach. It is possible to determine how it became a fossil since you can assume that it was either washed up on shore or buried by another animal. Clams generally live for about 400 years so in order for it to be a fossil it would have had to of been dead a long time ago which would be more than 400 years. It could of been around in the Silurian period or the Devonian period since that is when clams practically ruled the oceans. 252 million years ago is when clam like organisms were dominant so you have the general time it could of been around.

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If the condition change such that there are 4 mil at 4 atm and at 270 K, what is the new volume?
Juli2301 [7.4K]

Answer:

Increases in temperature tend to decrease density since volume will generally increase. There are exceptions however, such as water's density increasing between 0°C and 4°C. Below is a table of units in which density is commonly expressed, as well as the densities of some common materials.

Explanation:

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3 years ago
How many grams of oxygen are required to burn 3.01 x 10^23 propane molecules?
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The density of red wine is 1.01g/cm3 and the density of olive oil is 0.92g/cm3.A salad dressing that consisted of these two ingr
Sauron [17]

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3 0
3 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur
lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

q=m\times c\times \Delta T

q = heat absorbed by water

m = mass of water = 40.0 g

T_{final} = final temperature of water = 20.0°C

T_{initial = initial temperature of water = 17.0°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

q=40.0\times 4.186\times (20.0-17.0)]

q=502J

Hence, the joules of heat were re-leased by the lead is 502

5 0
3 years ago
What can we tell from the column that an element is in?
Paul [167]

Answer:

The number of electrons in the outer energy level

Explanation:

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