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lina2011 [118]
3 years ago
13

Need help please! Theres three parts to this that I don't understand at all

Chemistry
1 answer:
butalik [34]3 years ago
4 0

Answer:

Chemical reaction B governs the process

Explanation:

The first part of the question asks to convert the mass of the calcium carbonate given to number of moles.

Mathematically;

Number of moles = mass/molar mass

Molar mass of CaCO3 = 100 g/mol

So the number of moles of CaCO3 will be 2.49/100 = 0.0249 moles

The second part of the question asks to convert the mass of carbon iv oxide to moles of carbon iv oxide

Mathematically;

That is same as ;

Number of moles = mass/molar mass

molar mass of CO2 is 44 g/mol

Number of moles of CO2 = 1.13/44 = 0.0256 moles

Now, if we compare the values of these number of moles, we can see that there are almost equal.

What this means is that the number of moles of calcium carbonate reacted is equal to the number of moles of carbon iv oxide produced.

So what we conclude here is that we have an equal mole ratio between the two compounds.

So the reaction that would be the correct answer will present equal number of moles of carbon iv oxide and calcium carbonate

Thus, we can see that reaction B is the one that governs this process as it is the only reaction out of the three options that present the two compounds with equal number of moles.

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Answer:

137.9035 g

Explanation:

1 mole of copper in grams is 63.55 g

2.17 mole of Cu weighs 137.9035 g (63.55x2.17)

6 0
3 years ago
Suppose you believe your unknown compound is NaOH, and you prepare 20 mL of a 0.1 mol/L solution of it. The stockroom provides a
Alexus [3.1K]

Answer : Volume of HCl ( in ml)  is 10 ml.

Solution : Given,   Concentration of NaOH = 0.1 mol/L

                                Volume of NaOH = 20 ml

                                Concentration of HCl = 0.2 mol/L

                                 Volume of HCl =  ?

    Formula used :   Moles = Volume ×  Concentration

    In the reaction, we see that 1 mole of NaOH react with the 1 mole of HCl.

    so,

                       Moles of NaOH = Moles of HCl

    Moles of HCl = Moles of NaOH = Volume of NaOH ( in L) × Concentration of NaOH

    Converstion ml into L :      1000 ml = 1 L

             Moles of HCl =  \frac{20}{1000} × 0.1

                                    =  0.002 mol

             Volume of HCl = Moles / Comcentration of HCl

                                       = \frac{0.002 mole}{0.2mole/L}

                                       =  0.01 L

             Volume of HCl (in ml) =  0.01 × 1000 = 10 ml



7 0
3 years ago
Raising or lowering temperature. What happens to the pressure? Is this a direct or indirect relationship?
Dahasolnce [82]

Answer:

sorry I didn't understand this question

4 0
3 years ago
AlCl3 + Na NaCl + Al Did Cl change oxidation number?
gizmo_the_mogwai [7]
Yes. If this is the balanced equation:

AlCl3 + 3Na —— 3NaCl + Al

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6 0
3 years ago
Read 2 more answers
What volume of a 1.5 M KOH solution is needed to provide 3.0 moles of KOH?
Brums [2.3K]

Answer:

  • Volume = <u>2.0 liter</u> of 1.5 M solution of KOH

Explanation:

<u>1) Data:</u>

a) Solution: KOH

b) M = 1.5 M

c) n = 3.0 mol

d) V = ?

<u>2) Formula:</u>

Molarity is a unit of concentration, defined as number of moles of solute per liter of solution:

  • M = n / V in liter

<u>3) Calculations:</u>

  • Solve for n: M = n / V ⇒ V = n / M

  • Substitute values: V = 3.0 mol / 1.5 M = 2.0 liter

You must use 2 significant figures in your answer: <u>2.0 liter.</u>

8 0
3 years ago
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