For ___, 2 lobes have positive signs while the other 2 have negative signs, showing that the opposite lobes of have same sign.

Please help me due today at 7:00pm please help giving more points please help me

kkurt [141]

The answer is 20N as when the object is accelerating at 3 m/s2 it as a force of 10N applied to it so to get to 6m/s2 3(x2) = 6 so 10(x2) = 20

6 0

3 years ago

Question 5 (1 point)

Aleksandr-060686 [28]

Answer : The pressure it exert under these new conditions will be, 87 atm

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 19 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 100 L

$V_2$ = final volume of gas = 20 L

$T_1$ = initial temperature of gas = $25^oC=273+25=298K$

$T_2$ = final temperature of gas = $0^oC=273+0=273K$

Now put all the given values in the above equation, we get:

$\frac{19atm\times 100L}{298K}=\frac{P_2\times 20L}{273K}$

$P_2=87atm$

Therefore, the pressure it exert under these new conditions will be, 87 atm

5 0

3 years ago

What is another name for watershed

Sati [7]

Answer:

shed wadet

Explanation:

8 0

3 years ago

Jeff used an equal arm balance to weigh a 4.312 g sample of sodium chloride. Which of these measurements made by Jeff is the mos

Damm [24]

Option B: 4.3

There are following rules for rounding off numbers:

1. If the rounding digit has digit less than 5 (1,2,3 and 4) to its right, all the digits on right side of the rounding digit will drop out.

2. If the rounding digit has digit equal and greater than 5 (5,6,7,8 and 9) to its right, one is added to the rounding digit.

Jeff has to weigh 4.312 g sample of NaCl. To round off the underline number 4.<u>3</u>12, check for the digit right to it. It has 1, which is less than 5 thus according to the Rule 1, all the digits on right side of the rounding digit will drop out and the number gets rounded off to 4.3.

Therefore, 4.3 is most accurate measurement by Jeff.

7 0

3 years ago

Read 2 more answers

A reaction mixture initially contains 0.140 MCO and 0.140 MH2O. What will be the equilibrium concentration of CO?

Allushta [10]

Answer:

0.013 M

Explanation:

From the question, we can make the following deductions; we are given mixture that contains two compounds, that is A and B, 0.140 M CO and 0.140 M H2O respectively. Then, we are asked to find the equilibrium concentration of Carbonmonoxide,CO.

So, the equation for the reaction is given below;

CO + H2O <-----------------> CO2 + H2.

Initially: we have 0.14M of CO, 0.14M of H2O and zero (0) concentration of CO2 and H2.

At time,t = CO =0.14 - x , H2O = 0.14 - x, CO2 and H2 = x.

The above reaction consist of the forward reaction and the backward reaction.

Therefore, the equilibrium Concentration of CO;

(Since we are giving that Kc = 102). Then, Kc= [CO2][H2] ÷ [CO][H2O]. Where Kc is the equilibrium constant.

Therefore, 102 = [x^2] / [0.14 - x]^2.

==> 10.1= x/0.14 - x.

====> 0.141 - 10.1 x = x.

x + 10.1 x = 0.141.

===> 11.1 x = 0.141.

===> x = 0.141 ÷ 11.1.

===> x = 0.127 M .

Then, at time,t CO = 0.14 - x.

= 0.14 - 0.127 = 0.013 M

8 0

4 years ago

Read 2 more answers

For ___, 2 lobes have positive signs while the other 2 have negative signs, showing that the opposite lobes of have same sign.​

For ___, 2 lobes have positive signs while the other 2 have negative signs, showing that the opposite lobes of have same sign.