For ___, 2 lobes have positive signs while the other 2 have negative signs, showing that the opposite lobes of have same sign.

The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)

monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B Kc = TO BE DETERMINED

⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2 Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation: 2A + 2B ↔ A2B2 Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2 the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2) with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0

4 years ago

Write a balanced equation for the complete combustion of propane, C3H8 . Do not enter phase symbols. Enter the alkane formula as

Anastaziya [24]

Answer:

C3H8 + 5O2 => 3CO2 + 4H2O

Explanation:

Hydrocarbon combustion is the reaction between a hydrocarbon and O2 producing CO2 and water.

C3H8 + O2 => CO2 + H2O

First we balance the C and H.

C3H8 + O2 => 3CO2 + 4H2O

Now we balance O for the answer!

C3H8 + 5O2 => 3CO2 + 4H2O

3 0

3 years ago

2- A sheet of steel 3.0-mm thick has nitrogen atmospheres on both sides at 900Â°C and is permitted to achieve a steady-state dif

Bezzdna [24]

Answer:

2.78x10⁻³ m

Explanation:

Nitrogen diffusion in the steel can be expressed using the following equation:

$J = - D*\frac{\Delta C}{\Delta x} = - D*\frac{C_{1} - C_{2}}{x_{1} - x_{2}}$

<u>Where:</u>

J: is the diffusion flux = 1.0x10⁻⁷ kgm⁻²s⁻¹

D: is the diffusion coefficient = 1.85x10⁻¹⁰ m²/s

C₁: is the concentration of nitrogen in the steel at the surface = 2 kg/m³

C₂: is the concentration of nitrogen at the distance x₂ = 0.5 kg/m³

x₁: is the distance at the surface = 0

x₂: is the distance to find

Hence, we have:

$J = - D*\frac{C_{1} - C_{2}}{- x_{2}}$ (1)

Solving equation (1) for x₂:

$x_{2} = D \frac{C_{1} - C_{2}}{J} = 1.85 \cdot 10^{-10} m^{2}/s \frac{2 kg/m^{3} - 0.5 kg/m^{3}}{1.0 \cdot 10^{-7} kgm^{-2}s^{-1}} = 2.78 \cdot 10^{-3} m$

Therefore, the nitrogen will enter 2.78x10⁻³ m into the sheet.

I hope it helps you!

7 0

3 years ago

Why canâ€™t the calvin cycle run if the light reactions donâ€™t occur?

zysi [14]

Answer:

Because the Calvin cycle is dependent on the the product from light reaction.

Explanation:

The Calvin cycle is the light independent phase of photosynthesis during which carbon is fixed. This step requires energy generated during the light dependent phase of the photosynthesis.

Hence, if the light dependent reaction does not occur, the required energy to drive carbon fixation will be lacking and the Calvin cycle will not be able to proceed.

3 0

4 years ago

Is it true you will often have more control over the setting when photographing a pet versus a wild animal

Komok [63]

Answer: Sí

Explanation: ya que una mascota es inofensiva, pero para fotografiar a un animal salvaje, debes esperar pacientemente el momento perfecto

4 0

3 years ago

For ___, 2 lobes have positive signs while the other 2 have negative signs, showing that the opposite lobes of have same sign.​

For ___, 2 lobes have positive signs while the other 2 have negative signs, showing that the opposite lobes of have same sign.