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Studentka2010 [4]
3 years ago
9

Suppose you set a glass of water in direct sunlight for 2 hours and measure its temperature every 10 min . What type of graph wo

uld you use to display your data .
HELP ASAP PLS
Chemistry
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

line graph

Explanation:

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Which phrase best describes activation energy? (1 point)
iren [92.7K]

Answer: the minimum amount of energy required to break bonds and start a chemical reaction

Explanation: got a 100% on the quick check

8 0
2 years ago
The solid product from reaction of sulfuric acid with sucrose is?
Mama L [17]

\huge{\mathbb{\tt {QUESTION:}}}

The solid product from reaction of sulfuric acid with sucrose is?

\huge{\mathbb{\tt {ANSWER:}}}

  • Concentrated <u>sulfuric acid</u> is added to sucrose forming carbon, steam and <u>sulfur</u> dioxide.

<h2>--------------------------------------------------------------------------------</h2>

<h3>RELATED TO THE QUESTION </h3>

\huge{\mathbb{\tt {What \:  is \:  solid?:}}}

  • <u>Solid is one of the four fundamental states of matter</u>. The molecules in a solid are closely packed together and contain the least amount of kinetic energy.
  • <u>A solid is characterized by structural rigidity and resistance to a force applied to the surface</u>.

\huge{\mathbb{\tt {What \:  is \:  sulfur \:  acid?}}}

  • <u>Sulfuric acid or sulphuric acid, also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen</u>, with molecular formula H₂SO₄. It is a colorless, odorless and viscous liquid that is miscible with water at all concentrations.

\huge{\mathbb{\tt{What \:  is \:  sucrose?}}}

  • <u>Sucrose is common sugar. It is a disaccharide</u>, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.

#CarryOnLearning

#LetsEnjoyTheSummer

<h3>→XxKim02xX</h3>
6 0
2 years ago
If a catalyst is used in a reaction: question 13 options: the reaction rate increases. the reaction rate does not change. the eq
S_A_V [24]
The reaction rate increases.
8 0
3 years ago
Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure
Galina-37 [17]

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

\Delta T_f=i\times k_f\times m

where,

\DeltaT_b = change in freezing point

k_b = freezing point constant

m = molality

i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of KCl will be,

KCl\rightarrow K^++Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl_2(aq) at standard pressure is lower.

4 0
3 years ago
Which equation is derived from the combined gas law? StartFraction V subscript 1 over T subscript 1 EndFraction equals StartFrac
ioda

Answer:

\frac{V_!}{T_1} =\frac{V_2}{T_2}

Explanation:

hello,

the combined gas law equation is given as;

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

This combined gas law is gotten from the combination of Charles' law, Boyle's law and the Pressure law.

At constant pressure(this means the pressure is unchanged or fixed and this means the pressure is eliminated), we have:

\frac{V_1}{T_1} = \frac{V_2}{T_2}

At constant volume(we eliminate the volume since it is fixed or unchanged), we have;

\frac{P_1}{T_1} = \frac{P_2}{T_2}

At constant temperature (we also eliminate temperature), we have

P_1V_1 = P_2V_2.

thus from the options provided in the question the right answer will be

\frac{V_!}{T_!} = \frac{V_2}{T_2}

4 0
3 years ago
Read 2 more answers
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