Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.
So first, we take our measured value, .299 cm, minus our known value, .225 cm.
.299 cm - .225 cm=.004 cm
Next, we divide that by our known value
Finally, multiply your answer by 100
.0177777778 x 100= 1.77777778 %
Round to three significant figures, and you're done.
=1.78 % error
Answer:
A.
Explanation:
The number of the them will result in A.
Answer:
4 moles of carbon
6 moles of water
Explanation:
I think as there no data given u have to is the numbers infront of the equation e.g 4CO2 so 4.
hope this helps :)
The atom's radius and mass increase from top to bottom. The density of elements from top to bottom also increases in a periodic table.
Density of Sn= Mass of Sn/Volume of Sn
=24.3968/7.28
=3.49 g/ml*ml/cm³
=3.49 g/cm³
It is accurate to assume that the density of Sn will fall between that of Si and lead . the mass number and radius of the atoms increase from group to group as we move from top to bottom in a periodic table.. The density rises because the increase in mass number is greater than the increase in radius. Simply multiplying by the molar mass of the gas allows one to derive the formula for mass density from the formula for number density. Do not forget that the mass is equal to the moles (n) times the molar mass (M). Smaller masses can be measured in grams instead of kilograms (kg), which is the standard SI unit for mass.
To learn more about density please visit:
brainly.com/question/406690
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Answer:
HI (aq) → H⁺ (aq) + I⁻ (aq)
HI (aq) + H₂O(l) → H₃O⁺ (aq) + I⁻ (aq)
Explanation:
The Arrhenius acid concept indicates that a substance behaves like acid if it produces hydrogen ions H⁺ or hydronium ions H₃O⁺ in water. A substance will be classified as a base if it produces OH⁻ hydroxide ions in water. This way of defining acids and bases works well for aqueous solutions.
When we mix HI (aq) and water, we are increasing [H₃O⁺]
HI (aq) → H⁺ (aq) + I⁻ (aq)
HI (aq) + H₂O(l) → H₃O⁺ (aq) + I⁻ (aq)
