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emmainna [20.7K]
4 years ago
5

Which would be best categorized as heat transfer by conduction?

Chemistry
2 answers:
GalinKa [24]4 years ago
8 0

The answer is C) Feeling the heat from a light bulb with your hand when touching the bulb. :)

Maru [420]4 years ago
4 0

Answer: Option (C) is the correct answer.

Explanation:

When two substances or objects are at different temperature and heat from object 1 flows to object 2 when both of them are placed touching each other then this process is known as conduction.

For example, when we touch a light bulb then heat from the bulb flows into the hand.

Thus, we can conclude that out of the given options, feeling the heat from a light bulb with your hand when touching the bulb is best categorized as heat transfer by conduction.

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A student has a piece of aluminum metal. Which is the most reasonable assumption the student could make about the metal?
igor_vitrenko [27]

Aluminium belongs to 13th group of periodic table. It undergoes oxidation to given Al^+3 .

It is observed that when aluminium is added to a solution of copper sulphate the colour of the solution changes from blue to grey. It is due to formation of grey coloured solution of aluminium sulphate as

2Al^+3  + 3SO4^-2  ---> Al2(SO4)3


3 0
3 years ago
Read 2 more answers
Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
PLEASE HELP ASAPP!!!!! WILL MARK BRAINLIEST
Aloiza [94]

Answer:

400°C

Explanation:

22,000 cal / (0.11 cal/g°C x 500 g) = 400°C

3 0
3 years ago
Read 2 more answers
N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
kow [346]

Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

a-x=2.9M

Thus, the final concentration of N_2O_5 is, 2.9 M

3 0
3 years ago
Please help me out its due tmr :/
lesantik [10]

Answer:

using this for points, did you get the answer because I can try and help?

Explanation:

7 0
3 years ago
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