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viva [34]
3 years ago
14

The average velocity of molecules of nitrogen gas (N2) at room temperature is around 500 m/s. If you were to raise the temperatu

re of the nitrogen gas by 50°C what is a good estimate for the speed of the molecules?A. 100 m/sB. 500 m/sC. 600 m/sD. 200 m/s
Physics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

C

Explanation:

The speed of a molecule is directly related to its kinetic energy, which is directly related to the temperature. As the temperature increases, so does a molecule's speed. Of the options provided, only option C has a higher speed than 500m/s.

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Momentum data about the same objects in the same closed system is shown below.
nalin [4]

Answer:

the value of x is 3.7 because they are arranged in a particular manner.

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4 years ago
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Which projectiles will be visibly affected by air resistance when they fall?
NemiM [27]
Any object that is launched as a projectile will lose speed and, as a result, altitude, as it travels through the air. The rate at which the object loses speed and altitude depends on the amount of force that way applied to it when it was launched. It is also dependent on the size and shape of the item. This is why something like, say, a football is much faster to fall to the ground than a bullet.
4 0
3 years ago
A box of mass 26 kg is initially at rest on a flat floor. The coefficient of kinetic friction between the box and the floor is 0
Kazeer [188]

Answer:

\Delta K = 52J

Explanation:

The change in kinetic energy will be simply the difference between the final and initial kinetic energies: \Delta K=K_f-K_i

We know that the formula for the kinetic energy for an object is:

K=\frac{mv^2}{2}

where <em>m </em>is the mass of the object and <em>v</em> its velocity.

For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

Which for our values is:

\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

3 0
4 years ago
For an individual ( not a repair station) to conduct a complete 100 hour inspection on an aircraft and approve it for return to
Oliga [24]

Answer:

For an individual ( not a repair station) to conduct a complete 100 hour inspection on an aircraft and approve it for return to service requires a mechanic certificate with and powerplant and airframe ratings

Explanation:

Because these are important certificates issued by the FAA giving the mechanic authority to inspect to inspect an aircraft and approve its return to services

8 0
3 years ago
A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done inthe process.
dlinn [17]

Answer:

9.8 Joules (rounded to 2 significant figures)

Explanation:

Work done (J)= Force(N) x distance changed (m)

  • Force= 9.80665 x 0.5kg
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  • Distance changed= 5-3
  • distance changed= 2m/s

--> work done= 4.90332 x 2

work done= 9.8 Joules

5 0
3 years ago
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