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3 years ago

How to determine the number of valence electrons using the As and Bs system

Chemistry

1 answer:

xz_007 [3.2K]3 years ago

4 0

Answer:Use the K L M N shell orbit

Explanation: Valence electrons are those electrons on the outermost shell of an atomic nucleus.

The K L M N electron shell is named by a spectroscopist called Charles G. Barkla, who discovered the A X-rays ( high energy rays) and the B X-rays ( low energy rays), he later renamed the A X-rays K X-rays which is the Energy level orbit, and the B X-rays was also renamed to be the L M N and so on.

PLEASE SEE PICTURE ATTACHED

THE PICTURE SHOWS HOW TO DETERMINE VALENCE ELECTRON USING THE As AND B's WHICH ARE THE K L M N SHELL ORBIT, USING SILICON AS AN EXAMPLE.

The maximum number of electron in the K orbit is 2

The maximum number of electron in the L M N shell is 8

Therefore the number of electron found in the outermost shell becomes the number of Valence electron in that element.

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Explanation:

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3 years ago

Would you expect a Boron (B) atom with atomic mass = 9.999 to be stable?

charle [14.2K]

The balance of forces allows to find the result for the question if the isotope of boron 9.99 una is stable:

The boron isotope of mass 9.99 uma is unstable because the repulsive force increases.

The stability of atomic nuclei depends on the balance the force is electrostatic repulsion between the protons and the strong interaction of attraction.

One way to achieve this balance is to increase the separation of the protons with uncharged particles between them, the neutral ones, the strong interaction is of the same magnitude for protons and neutrons, therefore the repulsion is decreased and the strong attraction interaction is maintained. .

In the case of Boron, which has 5 protons, the stable structures have more atomistic 10 and 11 una, which is why it has 5 and 6 neutrons each. Therefore each proton has a neutrons next to it and in the other case a proton at the end has two neutrons, this causes the distance between the protons to increase, decreasing the electrostatic repulsion.

It indicates that we have a Boron nucleus of mass 9.999. The number of protons must remain fixed, therefore there are only 4 neutrons.

Consequently, some of the protons does not have a neutron next to it and can approach the other proton, therefore the electrostatic repulsion increases and the stability of the atom decreases.

In conclusion, using the balance of Forces we can find the result for the question if the isotope of boron 9.99 una is stable:

The boron isotope of mass 9.99 amu is unstable because the repulsive force increases.

Learn more about nuclear stability here: brainly.com/question/897383

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3 years ago

Croquet balls must have a mass of 0.50 kg. A red croquet ball, moving at 10

julsineya [31]

The final speed of the green ball : 8.5 m/s

<h3>Further explanation</h3>

Given

mass of Croquet ball = 0.5 kg

v₁= 10 m/s

v₁'= 1.5 m/s

Required

the final speed

Solution

The law of conservation of momentum

m₁v₁ + m₂v₂ = m₁v₁ '+ m₂v₂' (1=red croquet ball, 2=green croquet ball)

v₂=0 (at rest)

Input the value :

$\tt 0.5\times 10+0.5\times 0=0.5\times 1.5+0.5\times v_2'\\\\5=0.75+0.5v_2\\\\4.25=0.5v_2\rightarrow v_2=8.5~m/s$

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Volgvan

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3 years ago

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