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Pavlova-9 [17]
4 years ago
9

The complete orbital notation diagram of an atom is shown.

Chemistry
1 answer:
Yuki888 [10]4 years ago
8 0

Answer:

Explanation:

From the description provided by the statement of the problem, we can easily solve for the values of the angular momentum quantum number.

Let us represent the atom as J:

In atom J, we have five sub-orbitals in which there 9 electrons. From the designation used to represent sublevels, we can write the notation as below:

             J = 10 electrons = 1s² 2s² 2p⁵

The s-sublevel can only contain 2 electrons

p-sublevel can contain 6 electrons but we have just 5 electrons in there.

Now, to find the angular momentum quantum number, we need to understand what this quantum number denotes.

This quantum number is also known as azimuthal or secondary quantum number. It gives the shape of the orbitals in subshells accomodating electrons. This quantum number is designated by (l).

         l (n-1)            name of orbital               shape of orbital

             0                     s                                   spherical

             1                     p                                    dumb-bell

             2                    d                                    double dumb-bell

             3                    f                                      complex

J  = 1s² 2s² 2p⁵

where 1 and 2 coefficients are the principal quantum numbers(n).

            s and p are the shape of the orbitals

For 1s², the l vaue is 0 because the electron is in the s orbital

     2s² the l value is 0, 1 and the electron can be in the s or p orbitals

     2p⁵ the l value is 0, 1 and the electrons can be in the s or p orbitals

The quantum number gives the shape of the orbital.

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typical seawarer contains 2.7g of salt (sodium chloride,Nacl)per 100ml (100*10-3L).what is the molarity of Nacl in the ocean?​
faust18 [17]

Answer:

Molarity = 0.5 M

Explanation:

Given data:

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Molarity = number of moles / volume in litter

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3 years ago
1.25mole Nocl was placed in a2.50l reaction chamber at 427c. After equilibrium was reached .1.10moles of Nocl remained.Calculate
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Answer:

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Explanation:

Equilibrium reaction is:

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After the equilibrium, we have 1.10 moles. So, during the process:

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As ratio are 2:2, and 2:1, 0.15 moles of NO and (0.15 /2) = 0.075 moles of chlorine, were produced in the equilibrium.

Finally in equilibrium we have: 1.10 moles of NOCl, 0.15 moles of NO and 0.075 moles of Cl₂. But these amount are not molar, so we need molar concentration in order to determine Kc:

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Let's make expression for Kc → [Cl₂] . [NO]² / [NOCl]²

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