Answer:
There are 0.93 g of glucose in 100 mL of the final solution
Explanation:
In the first solution, the concentration of glucose (in g/L) is:
15.5 g / 0.100 L = 155 g/L
Then a 30.0 mL sample of this solution was taken and diluted to 0.500 L.
- 30.0 mL equals 0.030 L (Because 30.0 mL ÷ 1000 = 0.030 L)
The concentration of the second solution is:
So in 1 L of the second solution there are 9.3 g of glucose, in 100 mL (or 0.1 L) there would be:
1 L --------- 9.3 g
0.1 L--------- Xg
Xg = 9.3 g * 0.1 L / 1 L = 0.93 g
You got the answer correct. If you would double check
given:C (12 g/mol) H (1 g/mol).
12(8) + 1(8) = 104 g/mol
and for C2H4
12(2)+1(4) = 28g/mol
Also, chemical formula of styrene is<span> C6H5CH=CH2.</span>
Answer:
2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2
Explanation:
Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2
Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.
The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6
Answer:
The pellet fraction will be most radioactive because the heavy protein part of ghost will be present in the the pellet fraction.
Explanation:
supernatant can be defined as a liquid part that lies above the sediment of the centrifuge tube on the other hand pallet is a solid material present at the bottom end of the centrifuge tube.
As protein molecules in the given experiment is radio labelled that"s why the pellet fraction will be radio labeling part because the heavy protein molecules will be present in the pellet fraction.
