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Alinara [238K]
2 years ago
12

Solve the logarithmic equation. Be sure to reject any value that is not in the domain of the original logarithmic expressions. G

ive the exact answer. ln (x - 6) + ln (x + 1) = ln (x - 15)
Mathematics
1 answer:
Karolina [17]2 years ago
3 0
\bf \textit{logarithm of factors}\\\\
log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)\\\\
-------------------------------\\\\
ln(x-6)+ln(x+10)=ln(x-15)
\\\\\\
ln[(x-6)(x+10)]=ln(x-15)\implies (x-6)(x+10)=x-15
\\\\\\
x^2-5x-6=x-15\implies x^2-6x+9=0
\\\\\\
(x-3)^2=0\implies \boxed{x=3}

ok.. now, if we use  that on say ln(x-15), we end up with   \bf ln(-12)\implies log_e(-12).

now, there's no exponent whatsoever, that would give us a negative result for a base of "e", namely, x = 3 is NOT in the domain for ln(), so the system is inconsistent, or has no solution.
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