I think it's 2 I tried looking it up because I was not sure.
This may help you
<span>You need to use some stoichiometry here. The only way to do that is if you're working in moles. Since you're given grams of Al, you can convert that moles by dividing by the molar mass.
Then from looking at the coefficients in your equation, you can see that for however many moles of Al react, the same numbers of moles of Fe will be produced, but only half as many moles of Al2O3 will be produced.
To go back to grams, multiply the moles of each product that you get by their molar masses!</span>
C₃H₈ + 5 O₂ → 4 H₂O + 3 CO₂
mole ratio based on balance equation of O₂ : CO₂ i s 5 : 3
C₃H₈ + 5 O₂ → 4 H₂O + 3 CO₂
∴ if moles of CO₂ = 3 moles
then moles of O₂ = (3 moles ÷ 3) × 5
= <span>5 moles </span>
We are told that the concentration of sodium hypochlorite is 4.0% (w/v). To calculate the molarity of the sodium hypochlorite solution, let us consider a sample volume of 0.1 liter. Since we are given a w/v (Percent of weight of solution in the total volume of solution) value, it means that there are 4 <span>grams of sodium hypochlorite per 100 mL of solution (0.1 liter). Molarity is measured in moles per liter. So we'll just convert the given 4 grams to moles using the molar mass.
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4 grams</span>sodium hypochlorite * (1 mol sodium hypochlorite/ 74.44 g sodium hypochlorite) = 0.054 moles sodium hypochlorite
So we have 0.054 moles sodium hypochlorite / 0.1 L solution
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Thus the molarity is 0.53 mol/L or just 0.53 M.
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