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S_A_V [24]
3 years ago
14

!!29 POINTS!! PLS HELP ASAP

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

The person who just wanted points is annoying

Explanation:

WHY WOULD YOU DO THAT

You might be interested in
a _______ is a substance that comes out of solution when 2 clear liquids are mixed which is a sign of a _____ change.
Lena [83]

Answer:

precipitate , chemical

Explanation:

a precipitate is is an insoluble solid that forms when two solutions are combined and react chemically. The two clear colorless liquids is a chemical change because a different solid substance is formed

3 0
2 years ago
For a first-order reaction, A → B, the rate coefficient was found to be 3.4 × 10-4 s-1 at 23 °C. After 5.0 h, the concentration
Illusion [34]

Answer:

the original concentration of A = 0.0817092  M

Explanation:

A reaction is considered to be of first order it it strictly obeys the graphical equation method.

k_1 = \dfrac{2.303}{t}log \dfrac{a}{a-x}

where;

k = the specific rate coefficient  = 3.4 × 10⁻⁴ s⁻¹

t = time   = 5.0 h = 5.0 × 3600 = 18000 seconds

a = initial concentration = ???

a - x = remaining concentration of initial concentration at time t = 0.00018 mol L⁻¹

3.4 \times 10^{-4}= \dfrac{2.303}{18000}log \dfrac{a}{0.00018}

3.4 \times 10^{-4}= 1.27944 \times 10^{-4} \times log \dfrac{a}{0.00018}

\dfrac{3.4 \times 10^{-4}}{1.27944 \times 10^{-4}}=   log \dfrac{a}{0.00018}

2.657=   log \dfrac{a}{0.00018}

10^{2.657}= \dfrac{a}{0.00018}

453.94 = \dfrac{a}{0.00018}

a =453.94 \times 0.00018

a = 0.0817092  M

Thus , the original concentration of A = 0.0817092  M

8 0
3 years ago
What is the formula for barium iodide?
zysi [14]
Formula :  BaI₂. <span>barium iodide</span>
6 0
2 years ago
How much energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°c and completely vaporize the sample?
natta225 [31]

The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.

Calculation,

Given data,

Mass of the ice = 10 g

Temperature of ice =  0. 0°C

  • The ice at 0. 0°C is to be converted into water at 0. 0°C

Heat required at this stage = mas of the ice ×latent heat of fusion of ice

Heat required at this stage = 10 g×80 = 800 cal  

  • The temperature of the water is to be increased from 0. 0°C to 100. 0°C

Heat required for this = mass of the ice×rise in temperature×specific heat of water

Heat required for this  = 10 g×100× 1 = 1000 cal

  • This water at  100. 0°C  is to be converted into vapor.

Heat required for this = Mass of water× latent heat

Heat required for this  = 10g ×536 =5360 cal

Total energy or heat required = sum of all heat = 800 +1000+ 5360  = 7160 cal

to learn more about energy

brainly.com/question/7185299

#SPJ4

6 0
1 year ago
Blank are atoms that carry an electric charge
vampirchik [111]
Ions. Im 99.9% sure haha. 
8 0
3 years ago
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