Answer:
LR is Na₃PO₄
Explanation:
A quick way to determine the limiting reactant in a process is to convert reactant values to moles and then divide by the respective coefficient of the balanced equation. The smaller number of the division is the limiting reactant. For the given reaction, the rxn ratio of reactants is 1:1 so only the smaller mole value gives limiting reactant. However, if the reaction is NOT 1:1 the one must divide by respective coefficient to identify the smallest value and the limiting reactant.
This problem:
FeCl3(aq) + Na3PO4(aq) => FePO4(s) + 3 NaCl(aq)
Given: 27.8g 61.9g
moles: 27.8g/162.2g/mole 1.9g/163.94g/mole
= 0.1714 mole = 0.0116 mole
÷ coef. => 0.1714/1 = 0.1714 => 0.0116/1 = 0.0116
smaller value is LR => => => => => => LR is Na₃PO₄
Hope this helps. Doc :-)
Answer : The partial pressure of helium is, 
Solution : Given,
Molar mass of 
= 32 g/mole
Molar mass of helium = 4 g/mole
Molar mass of 
= 28 g/mole
Total pressure of gas = 
As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.
First we have to calculate the moles of oxygen, helium and nitrogen gas.
Now we have to calculate the total number of moles of gas mixture.
Now we have to calculate the moles fraction of helium gas.
Now we have to calculate the partial pressure of helium.
where,
= partial pressure of helium
= total pressure
= mole fraction of helium
Now put all the given values in this formula, we get
Therefore, the partial pressure of helium is,
Answer:
When the surface water is warm, the storm sucks up heat energy from the water, just like a straw sucks up a liquid. This creates moisture in the air. If wind conditions are right, the storm becomes a hurricane. This heat energy is the fuel for the storm.
Explanation:
I hope this can help you!
A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
When sodium carbonate is dissolved in water, the equation is 
.
When carbon dioxide is placed in water, aqueous carbon dioxide is formed: 
<h3>Dissolution of compounds in water</h3>
Some compounds are water-soluble, some are just partially soluble, while others are insoluble in water. Some soluble or partially soluble substances dissociate in water into their component ions. These substances are said to be ionic.
Sodium carbonate, like every other sodium salt, is soluble in water. It dissolves in water to form an aqueous solution of sodium carbonate.
While in solution, sodium carbonate dissociates into its component ions according to the following equation:
Carbon dioxide, on the other hand, does not dissociate in water. Instead, it dissolves in water where most of it remains as aqueous carbon dioxide in equilibrium with a small amount of hydronium ion and hydrogen carbonate ion.
Since the hydronium and hydrogen carbonate ions formed are so minute, the equation of the reaction can be written as:
More on the dissolution of substances can be found here: brainly.com/question/28580758
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