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Verdich [7]
2 years ago
13

JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the rhombus.

Mathematics
1 answer:
anygoal [31]2 years ago
5 0

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

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Read 2 more answers
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