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Verdich [7]
2 years ago
13

JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the rhombus.

Mathematics
1 answer:
anygoal [31]2 years ago
5 0

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

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Answer:

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2 years ago
The tength of a picture frame is 12 cm more than twice the width. If the perimeter is 204cm, find the
alekssr [168]

Answer:

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Step-by-step explanation:

The perimeter is the measurements of all sides added together. Let's start by dividing the perimeter by 2, so we have the sum of the length and width. This gives us 102cm. Let's call the width <em>x</em>, and the length <em>y</em>. We know <em>y</em> is <em>x</em> times 2 plus 12. (2x + 12) So, we know [x + y = x + (2x + 12)]. So let's solve.

x + y = x + (2x + 12)

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Read 2 more answers
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